krit.club logo

Algebra - Fibonacci, triangular, and other sequences

Grade 9IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

•

A sequence is an ordered list of numbers where each number is called a term, represented by unu_n or ana_n, where nn is the position of the term.

•

The Fibonacci sequence is a series where each number is the sum of the two preceding ones. It usually starts with 0,1,1,2,3,5,8,13,…0, 1, 1, 2, 3, 5, 8, 13, \dots.

•

Triangular numbers (1,3,6,10,15,…1, 3, 6, 10, 15, \dots) are numbers that can be represented as dots arranged in an equilateral triangle. The nthn^{th} triangular number is the sum of the first nn natural numbers.

•

Square numbers (1,4,9,16,…1, 4, 9, 16, \dots) are generated by the formula un=n2u_n = n^2.

•

Cube numbers (1,8,27,64,…1, 8, 27, 64, \dots) are generated by the formula un=n3u_n = n^3.

•

An Arithmetic Sequence (or Linear Sequence) has a constant difference dd between consecutive terms. The rule is of the form un=an+bu_n = an + b.

•

A Geometric Sequence involves multiplying the previous term by a constant ratio rr to get the next term.

📐Formulae

un=un−1+un−2u_n = u_{n-1} + u_{n-2}

Tn=n(n+1)2T_n = \frac{n(n + 1)}{2}

un=u1+(n−1)du_n = u_1 + (n - 1)d

un=u1×rn−1u_n = u_1 \times r^{n-1}

un=n2u_n = n^2

un=n3u_n = n^3

💡Examples

Problem 1:

Find the 15th15^{th} triangular number (T15T_{15}).

Solution:

T15=15(15+1)2T_{15} = \frac{15(15 + 1)}{2} T15=15×162T_{15} = \frac{15 \times 16}{2} T15=15×8=120T_{15} = 15 \times 8 = 120

Explanation:

To find any triangular number, use the formula Tn=n(n+1)2T_n = \frac{n(n+1)}{2} where nn is the position in the sequence.

Problem 2:

A Fibonacci-type sequence begins with u1=3u_1 = 3 and u2=8u_2 = 8. Find the value of u5u_5.

Solution:

u3=3+8=11u_3 = 3 + 8 = 11 u4=8+11=19u_4 = 8 + 11 = 19 u5=11+19=30u_5 = 11 + 19 = 30

Explanation:

In a Fibonacci sequence, each term is the sum of the two terms directly before it. We calculate u3u_3, then u4u_4, and finally u5u_5 using this recursive logic.

Problem 3:

Determine the nthn^{th} term formula for the sequence 7,11,15,19,…7, 11, 15, 19, \dots.

Solution:

First term u1=7u_1 = 7. Common difference d=11−7=4d = 11 - 7 = 4. un=u1+(n−1)du_n = u_1 + (n - 1)d un=7+(n−1)4u_n = 7 + (n - 1)4 un=7+4n−4u_n = 7 + 4n - 4 un=4n+3u_n = 4n + 3

Explanation:

This is an arithmetic sequence because the difference between terms is constant (d=4d = 4). We substitute the first term and the difference into the general arithmetic formula and simplify.