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Geometry and Measurement - The Pythagorean Theorem

Grade 7IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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The Pythagorean Theorem applies specifically to right-angled triangles. It defines the relationship between the two shorter sides (legs), denoted as aa and bb, and the longest side (hypotenuse), denoted as cc. The theorem states that a2+b2=c2a^2 + b^2 = c^2.

A right-angled triangle labeled with legs a and b, and hypotenuse c.
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The hypotenuse is always the side opposite the right angle (90∘90^{\circ}) and is the longest side of the triangle.

Diagram showing the relationship between the right angle and the hypotenuse.
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A 'Pythagorean Triple' is a set of three positive integers (a,b,c)(a, b, c) that perfectly satisfy the equation a2+b2=c2a^2 + b^2 = c^2. Common examples include (3,4,5)(3, 4, 5) and (8,15,17)(8, 15, 17).

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The Converse of the Pythagorean Theorem states that if the square of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is right-angled.

📐Formulae

a2+b2=c2a^2 + b^2 = c^2

c=a2+b2c = \sqrt{a^2 + b^2}

a=c2−b2a = \sqrt{c^2 - b^2}

b=c2−a2b = \sqrt{c^2 - a^2}

💡Examples

Problem 1:

A right-angled triangle has legs of length 5 cm5\text{ cm} and 12 cm12\text{ cm}. Calculate the length of the hypotenuse.

Solution:

Step 1: Identify the given values: a=5a = 5 and b=12b = 12. Step 2: Use the formula c2=a2+b2c^2 = a^2 + b^2. Step 3: Substitute the values: c2=52+122c^2 = 5^2 + 12^2. Step 4: Square the numbers: c2=25+144c^2 = 25 + 144. Step 5: Add the squares: c2=169c^2 = 169. Step 6: Solve for cc by taking the square root: c=169=13c = \sqrt{169} = 13. Final Answer: The hypotenuse is 13 cm13\text{ cm}.

Explanation:

To find the longest side (hypotenuse), we sum the squares of the two shorter sides and then take the square root of that sum.

Problem 2:

The hypotenuse of a right-angled triangle is 10 m10\text{ m} and one of the legs is 6 m6\text{ m}. Find the length of the other leg.

Solution:

Step 1: Identify the given values: c=10c = 10 and a=6a = 6. Step 2: Use the rearranged formula for a missing leg: b2=c2−a2b^2 = c^2 - a^2. Step 3: Substitute the values: b2=102−62b^2 = 10^2 - 6^2. Step 4: Square the numbers: b2=100−36b^2 = 100 - 36. Step 5: Subtract the values: b2=64b^2 = 64. Step 6: Solve for bb by taking the square root: b=64=8b = \sqrt{64} = 8. Final Answer: The length of the missing leg is 8 m8\text{ m}.

Explanation:

When the hypotenuse is already known, we must subtract the square of the known leg from the square of the hypotenuse before taking the square root.

Problem 3:

A ladder is leaning against a vertical wall. The base of the ladder is 9 m9\text{ m} away from the wall, and the ladder reaches a height of 12 m12\text{ m} up the wall. Calculate the length of the ladder.

A diagram of a ladder leaning against a wall forming a right-angled triangle.

Solution:

a2+b2=c2a^2 + b^2 = c^2 92+122=c29^2 + 12^2 = c^2 81+144=c281 + 144 = c^2 225=c2225 = c^2 c=225c = \sqrt{225} c=15 mc = 15\text{ m}

Explanation:

In this real-world scenario, the wall and the ground form a right angle. The distance from the wall (9 m9\text{ m}) and the height reached (12 m12\text{ m}) are the legs of a right-angled triangle. The ladder itself is the hypotenuse. We square both legs, sum them, and take the square root to find the ladder length.

Problem 4:

A rectangular field has a length of 24 m24\text{ m} and a diagonal of 25 m25\text{ m}. Find the width of the field.

A rectangle with a diagonal shown, forming a right-angled triangle.

Solution:

a2+b2=c2a^2 + b^2 = c^2 w2+242=252w^2 + 24^2 = 25^2 w2+576=625w^2 + 576 = 625 w2=625−576w^2 = 625 - 576 w2=49w^2 = 49 w=49w = \sqrt{49} w=7 mw = 7\text{ m}

Explanation:

A rectangle can be split into two right-angled triangles by its diagonal. Here, the diagonal acts as the hypotenuse (25 m25\text{ m}) and the length is one leg (24 m24\text{ m}). We rearrange the theorem to solve for the missing leg (width).