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Atoms and Molecules - Formula Unit Mass of Ionic Compounds

Grade 9CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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The formula unit mass of a substance is the sum of the atomic masses of all atoms in a formula unit of a compound.

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The term 'formula unit' is used for compounds whose constituent particles are ions (ionic compounds), such as NaClNaCl or K2CO3K_{2}CO_{3}, rather than discrete molecules.

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The calculation of formula unit mass is identical to the calculation of molecular mass; the only difference is the type of compound it refers to.

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The unit for formula unit mass is the unified mass unit, represented by uu.

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Ionic compounds exist as three-dimensional crystal lattices where ions are arranged in a specific ratio defined by the chemical formula.

📐Formulae

Formula Unit Mass=∑i=1n(ni×Ai)Formula\ Unit\ Mass = \sum_{i=1}^{n} (n_i \times A_i) (where nin_i is the number of atoms of element ii and AiA_i is its atomic mass)

Mass of Na2O=(2×Atomic mass of Na)+(1×Atomic mass of O)Mass\ of\ Na_{2}O = (2 \times \text{Atomic mass of } Na) + (1 \times \text{Atomic mass of } O)

💡Examples

Problem 1:

Calculate the formula unit mass of Zinc Oxide (ZnOZnO). (Given: Atomic mass of Zn=65 uZn = 65\ u, O=16 uO = 16\ u)

Solution:

Formula unit mass of ZnO=(1×65 u)+(1×16 u)Formula\ unit\ mass\ of\ ZnO = (1 \times 65\ u) + (1 \times 16\ u) 65+1681\begin{array}{r} 65 \\ + 16 \\ \hline 81 \end{array} Total mass = 81 u81\ u.

Explanation:

Since the formula ZnOZnO contains one atom of Zinc and one atom of Oxygen, we add their respective atomic masses together.

Problem 2:

Calculate the formula unit mass of Calcium Chloride (CaCl2CaCl_{2}). (Given: Atomic mass of Ca=40 uCa = 40\ u, Cl=35.5 uCl = 35.5\ u)

Solution:

Mass of Ca=1×40=40 uMass\ of\ Ca = 1 \times 40 = 40\ u Mass of 2×Cl=2×35.5=71 uMass\ of\ 2 \times Cl = 2 \times 35.5 = 71\ u Total: 40+71111\begin{array}{r} 40 \\ + 71 \\ \hline 111 \end{array} Total mass = 111 u111\ u.

Explanation:

In CaCl2CaCl_{2}, there is one Calcium ion and two Chloride ions. We multiply the mass of Chlorine by 22 and add it to the mass of Calcium.

Problem 3:

Find the formula unit mass of Potassium Carbonate (K2CO3K_{2}CO_{3}). (Given: K=39 u,C=12 u,O=16 uK = 39\ u, C = 12\ u, O = 16\ u)

Solution:

Mass of 2×K=2×39=78 uMass\ of\ 2 \times K = 2 \times 39 = 78\ u Mass of 1×C=1×12=12 uMass\ of\ 1 \times C = 1 \times 12 = 12\ u Mass of 3×O=3×16=48 uMass\ of\ 3 \times O = 3 \times 16 = 48\ u Total: 7812+48138\begin{array}{r} 78 \\ 12 \\ + 48 \\ \hline 138 \end{array} Result: 138 u138\ u.

Explanation:

The formula K2CO3K_{2}CO_{3} consists of two Potassium atoms, one Carbon atom, and three Oxygen atoms. Summing these masses gives the formula unit mass.