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Atoms and Molecules - Write chemical formulae and calculate molecular and formula unit mass

Grade 9CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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The chemical formula of a compound is a symbolic representation of its composition.

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The combining capacity (or binding capacity) of an element is known as its Valency. For example, the valency of Hydrogen is 11 and Oxygen is 22.

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An ion is a charged particle and can be negatively or positively charged. A negatively charged ion is called an anion (e.g., Cl−Cl^-) and a positively charged ion is called a cation (e.g., Na+Na^+).

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Polyatomic ions are a group of atoms carrying a charge, such as the Ammonium ion (NH4+NH_4^+) or the Hydroxide ion (OH−OH^-).

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When writing a chemical formula, the valencies or charges on the ions must balance.

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When a compound consists of a metal and a non-metal, the symbol of the metal is written first. For example: Iron Sulphide is written as FeSFeS and not SFeSFe.

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In compounds formed with polyatomic ions, the ion is enclosed in a bracket before writing the number to indicate the ratio, for example, Mg(OH)2Mg(OH)_2. Brackets are not needed if the number of ions is 11.

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The criss-cross method is used to write formulae: write the symbols of the combining elements, write their valencies below them, and then cross over the valencies of the combining atoms.

📐Formulae

Magnesium Chloride: Mg2++Cl1−→MgCl2\text{Magnesium Chloride: } Mg^{2+} + Cl^{1-} \rightarrow MgCl_2

Aluminium Oxide: Al3++O2−→Al2O3\text{Aluminium Oxide: } Al^{3+} + O^{2-} \rightarrow Al_2O_3

Calcium Oxide: Ca2++O2−→CaO (simplified from Ca2O2)\text{Calcium Oxide: } Ca^{2+} + O^{2-} \rightarrow CaO \text{ (simplified from } Ca_2O_2)

Sodium Carbonate: Na1++CO32−→Na2CO3\text{Sodium Carbonate: } Na^{1+} + CO_3^{2-} \rightarrow Na_2CO_3

Ammonium Sulphate: NH41++SO42−→(NH4)2SO4\text{Ammonium Sulphate: } NH_4^{1+} + SO_4^{2-} \rightarrow (NH_4)_2SO_4

💡Examples

Problem 1:

Write the chemical formula for Calcium Hydroxide.

Solution:

Ca(OH)2Ca(OH)_2

Explanation:

The symbol for Calcium is CaCa with a valency of 2+2+. The symbol for the Hydroxide ion is OHOH with a valency of 1−1-. Crossing the valencies, we get Ca1(OH)2Ca_1(OH)_2. We omit the subscript 11 and use brackets for the polyatomic ion OHOH to show that there are two hydroxide groups for every calcium atom.

Problem 2:

Determine the formula for Carbon Tetrachloride.

Solution:

CCl4CCl_4

Explanation:

The symbol for Carbon is CC (valency 44) and Chlorine is ClCl (valency 11). By criss-crossing the valencies, the 44 from Carbon goes to Chlorine and the 11 from Chlorine goes to Carbon, resulting in CCl4CCl_4.

Problem 3:

Write the formula for Aluminium Sulphate.

Solution:

Al2(SO4)3Al_2(SO_4)_3

Explanation:

Aluminium (AlAl) has a valency of 3+3+. The Sulphate ion (SO4SO_4) has a charge of 2−2-. When we criss-cross these values, the 22 becomes the subscript for AlAl and the 33 becomes the subscript for the entire SO4SO_4 group, requiring brackets: Al2(SO4)3Al_2(SO_4)_3.

Write chemical formulae and calculate molecular and formula unit mass Class 9 Notes & Examples