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Atoms and Molecules - Writing Chemical Formulae

Grade 9CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

The chemical formula of a compound is a symbolic representation of its composition.

The combining capacity (or binding capacity) of an element is known as its Valency. For example, the valency of Hydrogen is 11 and Oxygen is 22.

An ion is a charged particle and can be negatively or positively charged. A negatively charged ion is called an anion (e.g., ClCl^-) and a positively charged ion is called a cation (e.g., Na+Na^+).

Polyatomic ions are a group of atoms carrying a charge, such as the Ammonium ion (NH4+NH_4^+) or the Hydroxide ion (OHOH^-).

When writing a chemical formula, the valencies or charges on the ions must balance.

When a compound consists of a metal and a non-metal, the symbol of the metal is written first. For example: Iron Sulphide is written as FeSFeS and not SFeSFe.

In compounds formed with polyatomic ions, the ion is enclosed in a bracket before writing the number to indicate the ratio, for example, Mg(OH)2Mg(OH)_2. Brackets are not needed if the number of ions is 11.

The criss-cross method is used to write formulae: write the symbols of the combining elements, write their valencies below them, and then cross over the valencies of the combining atoms.

📐Formulae

Magnesium Chloride: Mg2++Cl1MgCl2\text{Magnesium Chloride: } Mg^{2+} + Cl^{1-} \rightarrow MgCl_2

Aluminium Oxide: Al3++O2Al2O3\text{Aluminium Oxide: } Al^{3+} + O^{2-} \rightarrow Al_2O_3

Calcium Oxide: Ca2++O2CaO (simplified from Ca2O2)\text{Calcium Oxide: } Ca^{2+} + O^{2-} \rightarrow CaO \text{ (simplified from } Ca_2O_2)

Sodium Carbonate: Na1++CO32Na2CO3\text{Sodium Carbonate: } Na^{1+} + CO_3^{2-} \rightarrow Na_2CO_3

Ammonium Sulphate: NH41++SO42(NH4)2SO4\text{Ammonium Sulphate: } NH_4^{1+} + SO_4^{2-} \rightarrow (NH_4)_2SO_4

💡Examples

Problem 1:

Write the chemical formula for Calcium Hydroxide.

Solution:

Ca(OH)2Ca(OH)_2

Explanation:

The symbol for Calcium is CaCa with a valency of 2+2+. The symbol for the Hydroxide ion is OHOH with a valency of 11-. Crossing the valencies, we get Ca1(OH)2Ca_1(OH)_2. We omit the subscript 11 and use brackets for the polyatomic ion OHOH to show that there are two hydroxide groups for every calcium atom.

Problem 2:

Determine the formula for Carbon Tetrachloride.

Solution:

CCl4CCl_4

Explanation:

The symbol for Carbon is CC (valency 44) and Chlorine is ClCl (valency 11). By criss-crossing the valencies, the 44 from Carbon goes to Chlorine and the 11 from Chlorine goes to Carbon, resulting in CCl4CCl_4.

Problem 3:

Write the formula for Aluminium Sulphate.

Solution:

Al2(SO4)3Al_2(SO_4)_3

Explanation:

Aluminium (AlAl) has a valency of 3+3+. The Sulphate ion (SO4SO_4) has a charge of 22-. When we criss-cross these values, the 22 becomes the subscript for AlAl and the 33 becomes the subscript for the entire SO4SO_4 group, requiring brackets: Al2(SO4)3Al_2(SO_4)_3.

Writing Chemical Formulae - Revision Notes & Key Formulas | CBSE Class 9 Science