krit.club logo

Algebra - General Rules and Formulas for Sequences

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

β€’

A sequence is an ordered list of numbers where each number is called a term, represented by u1,u2,u3,…,unu_1, u_2, u_3, \dots, u_n.

β€’

The position of a term in a sequence is denoted by nn, where n=1n = 1 for the first term, n=2n = 2 for the second, and so on.

β€’

A Linear (Arithmetic) Sequence is one where the difference between consecutive terms is constant. This constant is called the common difference dd.

β€’

The nthn^{th} term rule (position-to-term rule) allows us to find the value of any term in a sequence without listing all previous terms.

β€’

A Geometric Sequence is one where each term is found by multiplying the previous term by a constant value called the common ratio rr.

β€’

To find the common difference dd, subtract the first term from the second term: d=u2βˆ’u1d = u_2 - u_1.

πŸ“Formulae

un=a+(nβˆ’1)du_n = a + (n - 1)d

d=unβˆ’unβˆ’1d = u_{n} - u_{n-1}

un=dn+cΒ (whereΒ c=u1βˆ’d)u_n = dn + c \text{ (where } c = u_1 - d)

un=aΓ—r(nβˆ’1)u_n = a \times r^{(n-1)}

πŸ’‘Examples

Problem 1:

Find the nthn^{th} term rule for the sequence: 7,11,15,19,…7, 11, 15, 19, \dots

Solution:

un=4n+3u_n = 4n + 3

Explanation:

First, find the common difference dd: 11βˆ’7=411 - 7 = 4. This means the rule starts with 4n4n. To find the constant cc, look at the first term (n=1n=1): 4(1)+c=74(1) + c = 7, which gives c=3c = 3. Alternatively, subtract the difference from the first term: 7βˆ’4=37 - 4 = 3.

Problem 2:

For the sequence defined by un=5nβˆ’2u_n = 5n - 2, calculate the 25th25^{th} term.

Solution:

u25=123u_{25} = 123

Explanation:

Substitute n=25n = 25 into the formula: u25=5(25)βˆ’2u_{25} = 5(25) - 2. Calculating this gives 125βˆ’2=123125 - 2 = 123.

Problem 3:

Determine the first three terms of a geometric sequence where the first term a=3a = 3 and the common ratio r=2r = 2.

Solution:

3,6,123, 6, 12

Explanation:

The first term u1=3u_1 = 3. The second term u2=3Γ—2=6u_2 = 3 \times 2 = 6. The third term u3=6Γ—2=12u_3 = 6 \times 2 = 12.

Problem 4:

Is the number 5050 a term in the sequence un=3n+5u_n = 3n + 5?

Solution:

n=15n = 15

Explanation:

Set the formula equal to 5050: 3n+5=503n + 5 = 50. Subtract 55 from both sides: 3n=453n = 45. Divide by 33: n=15n = 15. Since 1515 is a whole number, 5050 is the 15th15^{th} term of the sequence.