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Biology - Food Chains and Food Webs

Grade 9IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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The Sun is the principal source of energy input to biological systems, providing the energy required for photosynthesis.

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Producers are organisms that make their own organic nutrients (like glucose) using energy from sunlight via photosynthesis: 6CO2+6H2O→lightC6H12O6+6O26CO_2 + 6H_2O \xrightarrow{\text{light}} C_6H_{12}O_6 + 6O_2

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Consumers are organisms that get their energy by feeding on other organisms. They are classified as primary consumers (herbivores), secondary consumers (carnivores that eat herbivores), and tertiary consumers (carnivores that eat other carnivores).

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A Trophic Level refers to the position of an organism in a food chain, food web, or ecological pyramid. Trophic level 1 is always the producer.

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Food Chains show the transfer of energy from one organism to the next, starting with a producer. The arrows represent the flow of energy.

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Food Webs are networks of interconnected food chains. They provide a more realistic model of ecosystem interactions because most consumers have more than one food source.

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Decomposers are organisms, such as bacteria and fungi, that get their energy from dead or waste organic matter.

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Energy is lost between trophic levels through processes such as respiration (heat loss), movement, excretion, and uneaten parts. Only approximately 10%10\% of energy is typically passed to the next level.

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Pyramids of Numbers represent the total number of individual organisms at each trophic level. They can be 'inverted' if a single large producer (like a tree) supports many small consumers.

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Pyramids of Biomass represent the total dry mass of living material at each trophic level. These are almost always pyramid-shaped because biomass is lost at each stage.

📐Formulae

Efficiency of Energy Transfer=(Energy available to the next trophic levelEnergy received from the previous trophic level)×100\text{Efficiency of Energy Transfer} = \left( \frac{\text{Energy available to the next trophic level}}{\text{Energy received from the previous trophic level}} \right) \times 100

Energy Lost=Total Energy Intake−Energy used for Growth (Biomass)\text{Energy Lost} = \text{Total Energy Intake} - \text{Energy used for Growth (Biomass)}

Percentage of Energy Lost=100%−Efficiency Percentage\text{Percentage of Energy Lost} = 100\% - \text{Efficiency Percentage}

💡Examples

Problem 1:

In a simple food chain: Grass →\rightarrow Grasshopper →\rightarrow Frog. If the Grass produces 25000 kJ25000\text{ kJ} of energy, and the efficiency of energy transfer to the Grasshopper is 10%10\%, how much energy is available to the Frog assuming a further 10%10\% transfer efficiency from the Grasshopper?

Solution:

Energy at Grasshopper level=25000×0.10=2500 kJ\text{Energy at Grasshopper level} = 25000 \times 0.10 = 2500\text{ kJ} Energy at Frog level=2500×0.10=250 kJ\text{Energy at Frog level} = 2500 \times 0.10 = 250\text{ kJ}

Explanation:

Energy is calculated step-by-step by multiplying the energy of the previous trophic level by the efficiency (10%10\% or 0.100.10). The frog, being at the third trophic level, receives only 1%1\% of the original producer's energy.

Problem 2:

A sheep consumes 12000 kJ12000\text{ kJ} of energy from grass. It loses 2400 kJ2400\text{ kJ} in feces, 7200 kJ7200\text{ kJ} through respiration, and 1200 kJ1200\text{ kJ} in urine. Calculate the energy available for the next trophic level (growth) and the efficiency of this transfer.

Solution:

24007200+120010800\begin{array}{r} 2400 \\ 7200 \\ + 1200 \\ \hline 10800 \end{array} Energy for growth=12000−10800=1200 kJ\text{Energy for growth} = 12000 - 10800 = 1200\text{ kJ} Efficiency=(120012000)×100=10%\text{Efficiency} = \left( \frac{1200}{12000} \right) \times 100 = 10\%

Explanation:

First, sum all the energy lost through various biological processes. Subtract this total from the initial intake to find the energy stored as biomass (growth). Finally, divide the growth energy by the total intake and multiply by 100100 to find the percentage efficiency.