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Biology - Energy Flow

Grade 9IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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The Sun is the principal source of energy input to biological systems. Energy enters the ecosystem through photosynthesis, where light energy is converted into chemical energy: 6CO2+6H2O→lightC6H12O6+6O26CO_{2} + 6H_{2}O \xrightarrow{\text{light}} C_{6}H_{12}O_{6} + 6O_{2}.

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A food chain shows the transfer of energy from one organism to the next, starting with a producer. The position of an organism in a food chain is its trophic level.

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Energy is transferred between trophic levels when one organism eats another. However, energy flow is non-cyclical; it moves in one direction and is eventually lost to the environment as heat.

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Efficiency of energy transfer is generally low, often cited as approximately 10%10\%. This means about 90%90\% of energy is lost at each level through respiration (C6H12O6+6O2→6CO2+6H2O+energyC_{6}H_{12}O_{6} + 6O_{2} \rightarrow 6CO_{2} + 6H_{2}O + \text{energy}), movement, excretion, and as heat.

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Pyramids of biomass represent the total dry mass of organisms at each level. Biomass typically decreases as you move up the pyramid due to the significant loss of energy and material at each stage.

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Pyramids of numbers show the total count of individual organisms. These can sometimes be inverted (e.g., one large oak tree supporting thousands of insects), whereas pyramids of energy are always upright.

📐Formulae

Efficiency of Energy Transfer=(Energy in higher trophic levelEnergy in lower trophic level)×100\text{Efficiency of Energy Transfer} = \left( \frac{\text{Energy in higher trophic level}}{\text{Energy in lower trophic level}} \right) \times 100

Energy Lost=Energy available at level n−Energy transferred to level n+1\text{Energy Lost} = \text{Energy available at level } n - \text{Energy transferred to level } n+1

💡Examples

Problem 1:

In a simple food chain: Grass →\rightarrow Rabbit →\rightarrow Fox, the energy available in the Grass is 80,000 kJ80,000\text{ kJ}. The energy successfully transferred to the Rabbit is 7,200 kJ7,200\text{ kJ}. Calculate the efficiency of this energy transfer.

Solution:

Efficiency=720080000×100=9%\text{Efficiency} = \frac{7200}{80000} \times 100 = 9\%

Explanation:

To find the efficiency, we divide the energy received by the consumer (7,200 kJ7,200\text{ kJ}) by the energy available in the producer (80,000 kJ80,000\text{ kJ}) and multiply by 100100 to get the percentage.

Problem 2:

If a primary consumer contains 2,500 kJ2,500\text{ kJ} of energy and only 225 kJ225\text{ kJ} is passed on to the secondary consumer, calculate the total energy lost to the environment using vertical subtraction.

Solution:

2500−2252275\begin{array}{r} 2500 \\ - 225 \\ \hline 2275 \end{array} Energy Lost = 2,275 kJ2,275\text{ kJ}

Explanation:

Energy lost is the difference between the energy consumed and the energy actually incorporated into the next trophic level. Here, 2,275 kJ2,275\text{ kJ} was lost as heat, waste, or used for metabolic processes.