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Biology - Transport in plants (Xylem, Phloem, and Transpiration)

Grade 9IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Xylem: Tissue responsible for the transport of water (H2OH_2O) and dissolved mineral ions from the roots to the leaves in a unidirectional flow (upwards).

Phloem: Tissue that transports sucrose (C12H22O11C_{12}H_{22}O_{11}) and amino acids from 'sources' (e.g., leaves) to 'sinks' (e.g., roots or flowers) in a process called translocation.

Root Hair Cells: Specialized cells with long extensions that increase the surface area for the absorption of water via osmosis and mineral ions via active transport.

Transpiration: The loss of water vapor from the aerial parts of a plant (mostly through the stomata in leaves) caused by evaporation at the surface of mesophyll cells.

The Transpiration Stream: The continuous column of water moving upwards through the xylem, maintained by cohesive forces between H2OH_2O molecules and adhesive forces between water and the xylem walls.

Factors affecting Transpiration: 1. Temperature (increases kinetic energy), 2. Humidity (decreases concentration gradient), 3. Wind speed (removes water vapor), 4. Light intensity (opens stomata).

Vascular Bundles: The arrangement of xylem and phloem; in the stem, xylem is located towards the center, while phloem is located towards the outside.

📐Formulae

Rate of Transpiration=Distance moved by air bubble (mm)Time taken (min)\text{Rate of Transpiration} = \frac{\text{Distance moved by air bubble (mm)}}{\text{Time taken (min)}}

Rate of Water Uptake=Volume of water absorbed (cm3)Time (h)\text{Rate of Water Uptake} = \frac{\text{Volume of water absorbed (cm}^3\text{)}}{\text{Time (h)}}

Ψleaf<Ψroot\Psi_{leaf} < \Psi_{root} (Movement of water from high water potential to low water potential)

💡Examples

Problem 1:

In a potometer experiment, the air bubble moved a distance of 6060 mm in 1212 minutes. Calculate the rate of transpiration.

Solution:

Rate=60 mm12 min=5 mm/min\text{Rate} = \frac{60 \text{ mm}}{12 \text{ min}} = 5 \text{ mm/min}

Explanation:

To find the rate of transpiration using a potometer, we divide the distance the bubble travels by the time it took to move that distance.

Problem 2:

Explain why increasing the humidity around a leaf decreases the rate of transpiration.

Solution:

High humidity increases the concentration of H2OH_2O molecules in the air outside the leaf, which reduces the concentration gradient between the internal air spaces and the atmosphere.

Explanation:

Transpiration relies on the diffusion of water vapor. According to Fick's Law, diffusion is faster when there is a steeper concentration gradient. High humidity makes the external air more like the internal air, slowing down the loss of H2OH_2O.

Problem 3:

Describe the structural adaptation of Xylem vessels for their function.

Solution:

Xylem vessels are made of dead cells joined end-to-end with no cross-walls (forming a continuous tube) and are reinforced with a waterproof substance called lignin.

Explanation:

The lack of cytoplasm and organelles provides an empty lumen for H2OH_2O flow, while lignin prevents the tubes from collapsing under the negative pressure of the transpiration pull.

Transport in plants (Xylem, Phloem, and Transpiration) Revision - Grade 9 Science IGCSE