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Geometry and Measure - Position and movement (Transformations)

Grade 7Cambridge (IGCSE)

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Translation involves shifting a shape in a specific direction without changing its size, orientation, or shape. This is defined by a vector (xy)\begin{pmatrix} x \\ y \end{pmatrix}, where xx represents horizontal displacement and yy represents vertical displacement.

A triangle translated by the vector (3, 1) on a coordinate grid.
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Reflection creates a mirror image of a shape across a line of reflection. Every point on the image is the same distance from the line as the corresponding point on the original object.

Reflection of a triangle across the y-axis.
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Rotation turns a shape around a fixed point called the center of rotation. You must specify the center (e.g., (0,0)(0,0)), the angle (e.g., 90∘90^\circ), and the direction (clockwise or anti-clockwise).

A triangle rotated 90 degrees anti-clockwise about the origin.
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Enlargement changes the size of a shape by a scale factor kk from a center of enlargement. If k>1k > 1, the shape gets larger; if 0<k<10 < k < 1, the shape gets smaller.

Enlargement of a triangle with scale factor 2 from the origin.

📐Formulae

Translation Vector: (xy)\begin{pmatrix} x \\ y \end{pmatrix} (where xx is horizontal movement and yy is vertical movement)

Scale Factor (kk): k=Image LengthObject Lengthk = \frac{\text{Image Length}}{\text{Object Length}}

Reflection in xx-axis: (x,y)→(x,−y)(x, y) \rightarrow (x, -y)

Reflection in yy-axis: (x,y)→(−x,y)(x, y) \rightarrow (-x, y)

Rotation 180∘180^\circ about origin: (x,y)→(−x,−y)(x, y) \rightarrow (-x, -y)

💡Examples

Problem 1:

A triangle with vertices A(1,2)A(1, 2), B(3,2)B(3, 2), and C(1,4)C(1, 4) is translated by the vector (2−3)\begin{pmatrix} 2 \\ -3 \end{pmatrix}. Find the new coordinates of A′A'.

Solution:

A′=(1+2,2−3)=(3,−1)A' = (1+2, 2-3) = (3, -1)

Explanation:

To translate a point, add the xx component of the vector to the xx-coordinate and the yy component of the vector to the yy-coordinate.

Problem 2:

Reflect the point P(4,5)P(4, 5) in the line y=xy = x.

Solution:

P′(5,4)P'(5, 4)

Explanation:

When reflecting in the line y=xy = x, the xx and yy coordinates are swapped.

Problem 3:

A square has a side length of 55 cm. It is enlarged by a scale factor of 33. What is the side length of the new square?

Solution:

5 cm×3=15 cm5 \text{ cm} \times 3 = 15 \text{ cm}

Explanation:

To find the new length after enlargement, multiply the original length by the scale factor kk.

Problem 4:

Rotate the point (2,0)(2, 0) 90∘90^\circ anti-clockwise about the origin (0,0)(0,0).

Solution:

(0,2)(0, 2)

Explanation:

A 90∘90^\circ anti-clockwise rotation moves a point from the positive xx-axis to the positive yy-axis.

Problem 5:

A rectangle has vertices at A(1,1)A(1, 1), B(3,1)B(3, 1), C(3,2)C(3, 2), and D(1,2)D(1, 2). It is reflected in the line y=3y = 3. Find the coordinates of the reflected image A′B′C′D′A'B'C'D'.

Rectangle reflected across the horizontal line y=3.

Solution:

  1. Identify the distance of each point from the line y=3y = 3.
  2. Point A(1,1)A(1, 1) is 22 units below the line, so A′A' will be 22 units above the line at (1,3+2)=(1,5)(1, 3+2) = (1, 5).
  3. Point B(3,1)B(3, 1) is 22 units below the line, so B′B' will be (3,5)(3, 5).
  4. Point C(3,2)C(3, 2) is 11 unit below the line, so C′C' will be (3,4)(3, 4).
  5. Point D(1,2)D(1, 2) is 11 unit below the line, so D′D' will be (1,4)(1, 4). Final coordinates: A′(1,5),B′(3,5),C′(3,4),D′(1,4)A'(1, 5), B'(3, 5), C'(3, 4), D'(1, 4).

Explanation:

Reflecting across a horizontal line y=ky=k keeps the xx-coordinate the same while the yy-coordinate changes such that the line is the midpoint.

Problem 6:

Rotate the triangle with vertices X(1,1)X(1, 1), Y(1,3)Y(1, 3), and Z(2,1)Z(2, 1) by 180∘180^\circ about the point (0,0)(0, 0).

Triangle rotated 180 degrees about the origin.

Solution:

For a rotation of 180∘180^\circ about the origin, the rule (x,y)→(−x,−y)(x, y) \rightarrow (-x, -y) applies.

  1. X(1,1)→X′(−1,−1)X(1, 1) \rightarrow X'(-1, -1)
  2. Y(1,3)→Y′(−1,−3)Y(1, 3) \rightarrow Y'(-1, -3)
  3. Z(2,1)→Z′(−2,−1)Z(2, 1) \rightarrow Z'(-2, -1)

Explanation:

A 180∘180^\circ rotation is equivalent to reflecting in both the xx and yy axes sequentially, effectively negating both coordinates.