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Exploring Mixtures and their Separation - Tyndall Effect

Grade 9CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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The Tyndall Effect is the phenomenon of scattering of a beam of light by colloidal particles or particles in a very fine suspension, making the path of light visible.

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In a True Solution, the particle size is less than 1 nm1 \text{ nm} (10−9 m10^{-9} \text{ m}). These particles are too small to scatter light; hence, true solutions do not show the Tyndall effect.

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In a Colloid, the particle size ranges between 1 nm1 \text{ nm} and 1000 nm1000 \text{ nm} (10−9 m10^{-9} \text{ m} to 10−6 m10^{-6} \text{ m}). These particles are large enough to scatter a beam of visible light.

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In a Suspension, particles are larger than 1000 nm1000 \text{ nm}. They scatter light when they are suspended in the medium, but the effect disappears if the particles settle down due to gravity.

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Common examples of the Tyndall effect include sunlight passing through a canopy of a dense forest (where mist acts as the colloid) and a beam of light entering a dark, dusty room through a small hole.

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The visibility of the path of light depends on the wavelength of light and the size of the scattering particles.

📐Formulae

Concentration of solution (Mass/Mass %)=Mass of soluteMass of solution×100\text{Concentration of solution (Mass/Mass \%)} = \frac{\text{Mass of solute}}{\text{Mass of solution}} \times 100

Mass of solution=Mass of solute+Mass of solvent\text{Mass of solution} = \text{Mass of solute} + \text{Mass of solvent}

Concentration of solution (Mass/Volume %)=Mass of soluteVolume of solution×100\text{Concentration of solution (Mass/Volume \%)} = \frac{\text{Mass of solute}}{\text{Volume of solution}} \times 100

💡Examples

Problem 1:

A solution contains 40 g40 \text{ g} of common salt in 320 g320 \text{ g} of water. Calculate the concentration in terms of mass by mass percentage of the solution. Will this solution show the Tyndall effect?

Solution:

Mass of solute (salt) = 40 g40 \text{ g}. Mass of solvent (water) = 320 g320 \text{ g}. Total mass of solution = 40 g+320 g=360 g40 \text{ g} + 320 \text{ g} = 360 \text{ g}. Concentration = 40360×100≈11.11%\frac{40}{360} \times 100 \approx 11.11\%. This solution will not show the Tyndall effect.

Explanation:

Since salt in water forms a true solution, the particle size is less than 1 nm1 \text{ nm}, which is insufficient to scatter light.

Problem 2:

Calculate the total mass of a solution if 20 g20 \text{ g} of solute is added to 180 g180 \text{ g} of solvent.

Solution:

20 g+180 g200 g\begin{array}{r} 20 \text{ g} \\ + 180 \text{ g} \\ \hline 200 \text{ g} \end{array}

Explanation:

The mass of a solution is the sum of the mass of the solute and the mass of the solvent.