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Exploring Mixtures and their Separation - How Can We Separate the Components of

Grade 9CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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A mixture contains more than one substance (element or compound) mixed in any proportion. Mixtures can be categorized as homogeneous (uniform composition) or heterogeneous (non-uniform composition).

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A solution is a homogeneous mixture of two or more substances. The component present in larger quantity is the solvent, and the component in smaller quantity is the solute.

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Concentration of a solution is the amount of solute present in a given amount (mass or volume) of solution, or the amount of solute dissolved in a given mass or volume of solvent.

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A saturated solution is one in which no more solute can be dissolved at a particular temperature. The amount of solute present in the saturated solution at this temperature is called its solubility.

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A suspension is a heterogeneous mixture in which the solute particles do not dissolve but remain suspended throughout the bulk of the medium. Particles are visible to the naked eye.

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A colloidal solution (colloid) is a heterogeneous mixture where particle size is too small to be seen individually but large enough to scatter light (Tyndall effect). Examples include milk, fog, and clouds.

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Separation techniques depend on the physical properties of components: Evaporation (separating volatile solvent from non-volatile solute), Centrifugation (separating denser particles from lighter particles), and Sublimation (separating a sublimable component like NH4ClNH_4Cl from a non-sublimable one).

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Chromatography is used for separation of those solutes that dissolve in the same solvent, such as pigments from natural colors or drugs from blood.

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Distillation is used for the separation of components of a mixture containing two miscible liquids that boil without decomposition and have a sufficient difference in their boiling points (>25 K> 25\text{ K}).

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Fractional Distillation is used if the difference in boiling points of miscible liquids is less than 25 K25\text{ K}. It is used for separating different gases from air or different fractions from petroleum products.

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Crystallization is a process that separates a pure solid in the form of its crystals from a solution. It is better than simple evaporation as it prevents decomposition of solids.

📐Formulae

Mass percentage of a solution=Mass of soluteMass of solution×100\text{Mass percentage of a solution} = \frac{\text{Mass of solute}}{\text{Mass of solution}} \times 100

Mass by volume percentage of a solution=Mass of soluteVolume of solution×100\text{Mass by volume percentage of a solution} = \frac{\text{Mass of solute}}{\text{Volume of solution}} \times 100

Volume by volume percentage of a solution=Volume of soluteVolume of solution×100\text{Volume by volume percentage of a solution} = \frac{\text{Volume of solute}}{\text{Volume of solution}} \times 100

Mass of solution=Mass of solute+Mass of solvent\text{Mass of solution} = \text{Mass of solute} + \text{Mass of solvent}

💡Examples

Problem 1:

A solution contains 40 g40\text{ g} of common salt in 320 g320\text{ g} of water. Calculate the concentration in terms of mass by mass percentage of the solution.

Solution:

Mass of solute (salt) = 40 g40\text{ g}. Mass of solvent (water) = 320 g320\text{ g}. Mass of solution = 40 g+320 g=360 g40\text{ g} + 320\text{ g} = 360\text{ g}. Concentration = 40360×100=11.1%\frac{40}{360} \times 100 = 11.1\%.

Explanation:

To find the mass percentage, we first calculate the total mass of the solution by adding the mass of the solute and solvent, then divide the solute's mass by the solution's mass and multiply by 100100.

Problem 2:

To make a saturated solution, 36 g36\text{ g} of sodium chloride is dissolved in 100 g100\text{ g} of water at 293 K293\text{ K}. Find its concentration at this temperature.

Solution:

Mass of solute=36 gMass of solvent=100 gMass of solution=136 g\begin{array}{r} \text{Mass of solute} = 36\text{ g} \\ \text{Mass of solvent} = 100\text{ g} \\ \hline \text{Mass of solution} = 136\text{ g} \end{array} Concentration = 36136×100≈26.47%\frac{36}{136} \times 100 \approx 26.47\%.

Explanation:

The concentration is calculated as the mass of NaClNaCl divided by the total mass of the saturated solution (NaCl+H2ONaCl + H_2O).

Problem 3:

How can we separate a mixture of two miscible liquids, Acetone (boiling point 56∘C56^\circ\text{C}) and Water (boiling point 100∘C100^\circ\text{C})?

Solution:

Since the difference in boiling points is 100∘C−56∘C=44∘C100^\circ\text{C} - 56^\circ\text{C} = 44^\circ\text{C} (which is >25 K> 25\text{ K}), we use Simple Distillation.

Explanation:

Acetone vaporizes first, is condensed in the condenser, and collected in a separate flask, leaving the water behind in the distillation flask.