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Biology: Genetics, Reproduction, and Biotechnology - Sexual and Asexual Reproduction and Life Cycles

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Asexual reproduction involves a single parent producing offspring that are genetically identical to the parent and to each other. This is achieved through cell division processes such as mitosis, where the chromosome number remains constant at 2n→2n2n \rightarrow 2n.

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Sexual reproduction requires the fusion of two specialized cells called gametes (sperm and egg). This process introduces genetic variation through the combination of DNA from two different parents.

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Meiosis is the specific type of cell division used to produce gametes. It reduces the chromosome number by half, shifting the state from diploid (2n2n) to haploid (nn).

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Fertilization is the union of a male gamete (nn) and a female gamete (nn) to form a zygote (2n2n). The zygote then undergoes mitosis to grow into a multicellular organism.

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Genetic variation in sexual reproduction is caused by independent assortment, crossing over during meiosis, and random fertilization, ensuring that offspring are not identical to their parents.

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Life cycles in organisms often alternate between a diploid phase and a haploid phase. In humans, the multicellular phase is 2n2n, while only the gametes are nn.

📐Formulae

n+n=2nn + n = 2n

Total Chromosomes (Diploid)=2n\text{Total Chromosomes (Diploid)} = 2n

Gamete Chromosomes (Haploid)=n=2n2\text{Gamete Chromosomes (Haploid)} = n = \frac{2n}{2}

Number of offspring (Binary Fission)=2i\text{Number of offspring (Binary Fission)} = 2^{i}

where i=number of generations\text{where } i = \text{number of generations}

💡Examples

Problem 1:

A human skin cell contains 4646 chromosomes. Calculate the number of chromosomes found in a human sperm cell and a human zygote.

Solution:

Sperm cell: 2323 chromosomes; Zygote: 4646 chromosomes.

Explanation:

A skin cell is a somatic cell, which is diploid (2n=462n = 46). A sperm cell is a gamete and must be haploid (nn), so n=462=23n = \frac{46}{2} = 23. A zygote is formed by the fusion of two gametes (n+nn + n), returning the count to 23+23=4623 + 23 = 46 chromosomes.

Problem 2:

A specific species of fern has a diploid number of 2n=12002n = 1200. How many chromosomes are present in its spores if spores are produced via meiosis?

Solution:

600600 chromosomes.

Explanation:

Meiosis reduces the chromosome number by half (2n→n2n \rightarrow n). Therefore, the number of chromosomes in the haploid spore is n=12002=600n = \frac{1200}{2} = 600.

Problem 3:

A bacterium reproduces asexually via binary fission every 2020 minutes. If you start with 11 bacterium, how many bacteria will be present after 11 hour (6060 minutes)?

Solution:

88 bacteria.

Explanation:

First, find the number of generations (ii): i=60 mins20 mins=3i = \frac{60 \text{ mins}}{20 \text{ mins}} = 3. Using the formula 2i2^i, we get 23=2×2×2=82^3 = 2 \times 2 \times 2 = 8.

Sexual and Asexual Reproduction and Life Cycles Grade 8 Notes & Examples