krit.club logo

Biology: Genetics, Reproduction, and Biotechnology - Mendelian Inheritance, Variation, and Genetic Disorders

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

•

Mendelian Inheritance: Gregor Mendel's principles explain how traits are passed from parents to offspring. The Law of Segregation states that an individual possesses two alleles for a trait, which separate during gamete formation (AA and aa).

•

Genotype vs. Phenotype: The Genotype is the genetic constitution of an organism (e.g., TTTT, TtTt, or tttt), while the Phenotype is the observable physical characteristic (e.g., Tall or Short).

•

Dominance and Recessiveness: A dominant allele (TT) masks the effect of a recessive allele (tt). For a recessive trait to be expressed, the organism must be homozygous recessive (tttt).

•

Homozygous vs. Heterozygous: An organism with two identical alleles is Homozygous (BBBB or bbbb). An organism with two different alleles is Heterozygous (BbBb).

•

Variation: Differences between individuals of the same species. Continuous Variation (e.g., height, weight) is influenced by multiple genes and the environment. Discontinuous Variation (e.g., blood group, ability to roll tongue) is usually controlled by a single gene and falls into distinct categories.

•

Genetic Disorders: These are caused by DNA mutations. For example, Cystic Fibrosis is an autosomal recessive disorder; an individual must inherit the genotype ffff to have the disease. Carriers have the genotype FfFf.

•

Biotechnology: Involves using living organisms or biological systems to develop products. Genetic Engineering involves altering the DNA of an organism to produce desired traits, such as insulin-producing bacteria.

📐Formulae

Phenotypic Ratio (Monohybrid Cross Tt×Tt)=3:1\text{Phenotypic Ratio (Monohybrid Cross } Tt \times Tt) = 3 : 1

Genotypic Ratio (Monohybrid Cross Tt×Tt)=1:2:1\text{Genotypic Ratio (Monohybrid Cross } Tt \times Tt) = 1 : 2 : 1

Probability of Trait=Number of specific genotypesTotal number of possible genotypes\text{Probability of Trait} = \frac{\text{Number of specific genotypes}}{\text{Total number of possible genotypes}}

Dihybrid Cross Phenotypic Ratio=9:3:3:1\text{Dihybrid Cross Phenotypic Ratio} = 9 : 3 : 3 : 1

💡Examples

Problem 1:

In pea plants, round seeds (RR) are dominant over wrinkled seeds (rr). If a heterozygous round-seeded plant (RrRr) is crossed with a wrinkled-seeded plant (rrrr), what is the probability that the offspring will have wrinkled seeds?

Solution:

The probability is 50%50\% or 12\frac{1}{2}.

Explanation:

We use a Punnett Square to determine the genotypes of the offspring from the cross Rr×rrRr \times rr:

RrrRrrrrRrrr\begin{array}{|c|c|c|} \hline & R & r \\ \hline r & Rr & rr \\ \hline r & Rr & rr \\ \hline \end{array}

The resulting genotypes are 2×Rr2 \times Rr (Heterozygous Round) and 2×rr2 \times rr (Homozygous Wrinkled). Probability of wrinkled seeds (rrrr) = 24=0.5\frac{2}{4} = 0.5 or 50%50\%.

Problem 2:

A couple are both carriers for Sickle Cell Anemia, an autosomal recessive disorder. If their genotypes are both AaAa, calculate the percentage chance that their child will be a carrier (AaAa) and the chance the child will have the disease (aaaa).

Solution:

Carrier chance: 50%50\%; Disease chance: 25%25\%.

Explanation:

The cross is Aa×AaAa \times Aa:

AaAAAAaaAaaa\begin{array}{|c|c|c|} \hline & A & a \\ \hline A & AA & Aa \\ \hline a & Aa & aa \\ \hline \end{array}

  • Genotype AAAA (Normal): 11 out of 44 (25%25\%)
  • Genotype AaAa (Carrier): 22 out of 44 (50%50\%)
  • Genotype aaaa (Affected): 11 out of 44 (25%25\%)