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Biology: Biochemistry and Plant Physiology - Biological Molecules, Biochemistry, and Metabolism

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Biological molecules are the building blocks of life, categorized into four main types: carbohydrates, lipids, proteins, and nucleic acids.

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Carbohydrates are composed of carbon, hydrogen, and oxygen, typically in a ratio of 1:2:11:2:1. The basic monomer is a monosaccharide, such as glucose (C6H12O6C_6H_{12}O_6).

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Lipids (fats and oils) are hydrophobic molecules used for long-term energy storage and cell membrane structure. They are primarily composed of glycerol and fatty acid chains.

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Proteins are polymers of amino acids linked by peptide bonds. They function as enzymes, structural components, and signaling molecules. Each amino acid contains an amine group (−NH2-NH_2) and a carboxyl group (−COOH-COOH).

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Enzymes are biological catalysts that speed up chemical reactions by lowering the activation energy (EaE_a) required for the reaction to occur.

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Metabolism is the sum of all chemical reactions in an organism, consisting of catabolism (breaking down molecules to release energy) and anabolism (using energy to build complex molecules).

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Photosynthesis is the process by which plants convert light energy into chemical energy, occurring in the chloroplasts. The primary pigment involved is chlorophyll.

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Cellular Respiration is the process of breaking down glucose to produce Adenosine Triphosphate (ATPATP), which serves as the universal energy currency for cells.

📐Formulae

C6H12O6+6O2→6CO2+6H2O+Energy (ATP)C_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O + \text{Energy (ATP)}

6CO2+6H2O→Light/ChlorophyllC6H12O6+6O26CO_2 + 6H_2O \xrightarrow{\text{Light/Chlorophyll}} C_6H_{12}O_6 + 6O_2

Cn(H2O)nC_n(H_2O)_n

Rate of Reaction=ΔProductΔTime\text{Rate of Reaction} = \frac{\Delta \text{Product}}{\Delta \text{Time}}

C6H12O6→2C3H6O3+2 ATP (Lactic Acid Fermentation)C_6H_{12}O_6 \rightarrow 2C_3H_6O_3 + \text{2 ATP (Lactic Acid Fermentation)}

💡Examples

Problem 1:

Calculate the ratio of Hydrogen to Oxygen atoms in a sucrose molecule with the formula C12H22O11C_{12}H_{22}O_{11}.

Solution:

Ratio=2211=21\text{Ratio} = \frac{22}{11} = \frac{2}{1}

Explanation:

In sucrose, there are 2222 atoms of Hydrogen and 1111 atoms of Oxygen. Dividing both by 1111 gives a ratio of 2:12:1, which is characteristic of most carbohydrates.

Problem 2:

If a plant produces 3030 moles of glucose (C6H12O6C_6H_{12}O_6) during photosynthesis, how many moles of Carbon Dioxide (CO2CO_2) were consumed, assuming the reaction goes to completion?

Solution:

30×6=180 moles of CO230 \times 6 = 180 \text{ moles of } CO_2

Explanation:

According to the balanced equation 6CO2+6H2O→C6H12O6+6O26CO_2 + 6H_2O \rightarrow C_6H_{12}O_6 + 6O_2, it takes 66 molecules of CO2CO_2 to produce 11 molecule of glucose. Therefore, 30 moles×6=180 moles30 \text{ moles} \times 6 = 180 \text{ moles}.

Problem 3:

An enzyme-catalyzed reaction produces 150 mg150\text{ mg} of product in 55 minutes. Calculate the rate of reaction in mg/min\text{mg/min}.

Solution:

Rate=150 mg5 min=30 mg/min\text{Rate} = \frac{150\text{ mg}}{5\text{ min}} = 30\text{ mg/min}

Explanation:

The rate of a biochemical reaction is determined by the change in the amount of product over the change in time.