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Biology: Biochemistry and Plant Physiology - Aerobic and Anaerobic Respiration (Glycolysis, Krebs Cycle, Electron Transport, and ATP)

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Cellular Respiration is the process by which cells break down glucose (C6H12O6C_6H_{12}O_6) to release energy in the form of Adenosine Triphosphate (ATPATP).

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Aerobic Respiration occurs in the presence of oxygen (O2O_2) and is highly efficient, producing approximately 3636 to 3838 molecules of ATPATP per molecule of glucose.

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Glycolysis is the first stage of respiration, occurring in the cytoplasm. It breaks down one molecule of glucose (66-carbon) into two molecules of pyruvate (33-carbon), yielding a net gain of 2 ATP2\ ATP and 2 NADH2\ NADH.

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The Krebs Cycle (Citric Acid Cycle) takes place in the mitochondrial matrix. It processes pyruvate to produce CO2CO_2, ATPATP, and electron carriers (NADHNADH and FADH2FADH_2).

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The Electron Transport Chain (ETC) occurs in the inner mitochondrial membrane (cristae). It uses electrons from NADHNADH and FADH2FADH_2 to create a proton gradient that powers ATP synthaseATP\ synthase to produce the bulk of the cell's ATPATP.

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Anaerobic Respiration (Fermentation) occurs in the absence of O2O_2 in the cytoplasm. It produces only 2 ATP2\ ATP per glucose molecule.

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In animals, anaerobic respiration produces Lactic Acid (C3H6O3C_3H_6O_3), leading to muscle fatigue: C6H12O6→2C3H6O3+2 ATPC_6H_{12}O_6 \rightarrow 2C_3H_6O_3 + 2\ ATP.

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In plants and yeast, anaerobic respiration (Alcoholic Fermentation) produces Ethanol (C2H5OHC_2H_5OH) and Carbon Dioxide (CO2CO_2): C6H12O6→2C2H5OH+2CO2+2 ATPC_6H_{12}O_6 \rightarrow 2C_2H_5OH + 2CO_2 + 2\ ATP.

📐Formulae

C6H12O6+6O2→6CO2+6H2O+Energy (36−38 ATP)C_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O + Energy\ (36-38\ ATP)

ADP+Pi+Energy⇌ATP+H2OADP + P_i + Energy \rightleftharpoons ATP + H_2O

C6H12O6→2C3H6O3+2 ATP (Lactic Acid Fermentation)C_6H_{12}O_6 \rightarrow 2C_3H_6O_3 + 2\ ATP\ (Lactic\ Acid\ Fermentation)

C6H12O6→2C2H5OH+2CO2+2 ATP (Alcoholic Fermentation)C_6H_{12}O_6 \rightarrow 2C_2H_5OH + 2CO_2 + 2\ ATP\ (Alcoholic\ Fermentation)

💡Examples

Problem 1:

During a sprint, a student's muscle cells run low on oxygen. If 55 molecules of glucose are metabolized anaerobically, how many molecules of ATPATP are produced compared to aerobic respiration?

Solution:

Anaerobic ATP=10ATP = 10; Aerobic ATP=180ATP = 180.

Explanation:

In anaerobic respiration, each glucose molecule yields 2 ATP2\ ATP. For 55 molecules: 5×2=10 ATP5 \times 2 = 10\ ATP. In aerobic respiration, each glucose yields roughly 36 ATP36\ ATP. For 55 molecules: 5×36=180 ATP5 \times 36 = 180\ ATP.

Problem 2:

Identify the location and the net yield of ATPATP and NADHNADH during the Glycolysis phase for 22 molecules of glucose.

Solution:

Location: Cytoplasm; Net yield: 4 ATP4\ ATP and 4 NADH4\ NADH.

Explanation:

Glycolysis occurs in the cytoplasm. A single glucose molecule produces a net of 2 ATP2\ ATP and 2 NADH2\ NADH. Therefore, 22 molecules of glucose will produce 2×2=4 ATP2 \times 2 = 4\ ATP and 2×2=4 NADH2 \times 2 = 4\ NADH.