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Materials Around Us - What is Matter?

Grade 6CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Matter is defined as anything that occupies space (has volume) and has mass (mm).

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Matter is made up of tiny particles. The arrangement of these particles determines the state of matter.

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Solids: Particles are tightly packed in a regular pattern. Solids have a fixed shape and a fixed volume.

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Liquids: Particles are close together but can move past each other. Liquids have a fixed volume but no fixed shape (they take the shape of the container).

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Gases: Particles are far apart and move randomly at high speeds. Gases have neither a fixed shape nor a fixed volume.

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Mass is the quantity of matter contained in an object, usually measured in kilograms (kgkg) or grams (gg).

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Volume is the amount of space occupied by an object, measured in liters (LL) or cubic centimeters (cm3cm^3).

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Density is the mass per unit volume (ρ=mV\rho = \frac{m}{V}). Objects with a density higher than water (1g/cm31 g/cm^3) will sink, while those with lower density will float.

📐Formulae

Density(ρ)=Mass(m)Volume(V)Density (\rho) = \frac{Mass (m)}{Volume (V)}

Volume=length×width×heightVolume = length \times width \times height

1kg=1000g1 kg = 1000 g

1L=1000mL=1000cm31 L = 1000 mL = 1000 cm^3

💡Examples

Problem 1:

A wooden block has a mass of 120g120 g and a volume of 150cm3150 cm^3. Calculate its density and determine if it will float in water (Density of water = 1g/cm31 g/cm^3).

Solution:

Density=120g150cm3=0.8g/cm3Density = \frac{120 g}{150 cm^3} = 0.8 g/cm^3

Explanation:

Since the density of the wooden block (0.8g/cm30.8 g/cm^3) is less than the density of water (1.0g/cm31.0 g/cm^3), the block will float.

Problem 2:

Calculate the total mass of two metal spheres if Sphere A weighs 1250g1250 g and Sphere B weighs 875g875 g. Use vertical addition.

Solution:

1250+8752125\begin{array}{r} 1250 \\ + 875 \\ \hline 2125 \end{array}

Explanation:

The total mass is calculated by adding the mass of Sphere A and Sphere B, resulting in 2125g2125 g or 2.125kg2.125 kg.

Problem 3:

An irregular stone is dropped into a measuring cylinder containing 50mL50 mL of water. The water level rises to 75mL75 mL. What is the volume of the stone?

Solution:

Volume=75mL−50mL=25mLVolume = 75 mL - 50 mL = 25 mL

Explanation:

The volume of an object submerged in a liquid is equal to the volume of the liquid displaced by it. Thus, V=25mLV = 25 mL or 25cm325 cm^3.