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Algebra - Proportion

Grade 9IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Direct Proportion: Two quantities xx and yy are in direct proportion if they increase or decrease in the same ratio. This is written as y∝xy \propto x, which implies y=kxy = kx, where kk is the constant of proportionality.

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Inverse Proportion: Two quantities xx and yy are in inverse proportion if one increases while the other decreases in the same ratio. This is written as y∝1xy \propto \frac{1}{x}, which implies y=kxy = \frac{k}{x}.

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Proportion with Powers: Variables can be proportional to squares, cubes, or square roots. For example, if yy is proportional to the square of xx, then y=kx2y = kx^2.

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Finding the Constant kk: To solve any proportion problem, first use the given values of the variables to calculate the value of kk.

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Graphs: A graph of direct proportion (y=kxy = kx) is a straight line passing through the origin (0,0)(0,0). A graph of inverse proportion (y=kxy = \frac{k}{x}) is a hyperbola that never touches the axes.

📐Formulae

y=kxy = kx

y=kxy = \frac{k}{x}

y=kx2y = kx^2

y=kx2y = \frac{k}{x^2}

y=kxy = k\sqrt{x}

💡Examples

Problem 1:

yy is directly proportional to xx. Given that y=15y = 15 when x=3x = 3, find the value of yy when x=10x = 10.

Solution:

Step 1: Write the general equation. y=kxy = kx Step 2: Substitute the known values to find kk. 15=k×315 = k \times 3 k=153=5k = \frac{15}{3} = 5 Step 3: Write the specific formula. y=5xy = 5x Step 4: Substitute x=10x = 10 to find yy. y=5×10=50y = 5 \times 10 = 50

Explanation:

Since yy is directly proportional to xx, we use the linear relationship y=kxy=kx. We find the constant kk first and then use it to find the unknown value.

Problem 2:

hh is inversely proportional to r2r^2. When r=2r = 2, h=9h = 9. Find hh when r=3r = 3.

Solution:

Step 1: Write the general equation. h=kr2h = \frac{k}{r^2} Step 2: Substitute the known values to find kk. 9=k229 = \frac{k}{2^2} 9=k49 = \frac{k}{4} k=36k = 36 Step 3: Write the specific formula. h=36r2h = \frac{36}{r^2} Step 4: Substitute r=3r = 3 to find hh. h=3632h = \frac{36}{3^2} h=369=4h = \frac{36}{9} = 4

Explanation:

Inverse proportion means hh is equal to kk divided by the square of rr. Once the constant k=36k=36 is established, we solve for hh using the new value of rr.

Problem 3:

The time TT taken for a pendulum to swing is proportional to the square root of its length LL. If T=2T = 2 seconds when L=16L = 16 cm, find TT when L=64L = 64 cm.

Solution:

Step 1: Write the equation. T=kLT = k\sqrt{L} Step 2: Find kk. 2=k162 = k\sqrt{16} 2=k×42 = k \times 4 k=24=0.5k = \frac{2}{4} = 0.5 Step 3: Substitute L=64L = 64. T=0.5×64T = 0.5 \times \sqrt{64} T=0.5×8=4T = 0.5 \times 8 = 4

Explanation:

This is a direct proportion involving a square root. We solve for kk using the square root of the initial length, then apply it to the new length.