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Human Physiology - Digestion, Absorption, and Egestion

Grade 9IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Digestion is the process of breaking down large, insoluble food molecules into small, soluble molecules that can be absorbed into the bloodstream. It occurs through mechanical means (chewing, churning) and chemical means (hydrolysis catalyzed by enzymes).

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Chemical digestion involves enzymes, which are biological catalysts. The general reaction for hydrolysis of a macronutrient is: Substrate+H2O→EnzymeProductsSubstrate + H_{2}O \xrightarrow{Enzyme} Products.

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Carbohydrate digestion: Starch is broken down by Amylase into Maltose, and then by Maltase into Glucose. The simple sugar Glucose has the formula C6H12O6C_{6}H_{12}O_{6}.

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Protein digestion: Proteins are broken down by Proteases (like Pepsin in the stomach and Trypsin in the small intestine) into Polypeptides and eventually into Amino Acids.

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Lipid digestion: Fats are emulsified by bile and then broken down by Lipase into Glycerol and Fatty Acids. The reaction consumes water: Triglyceride+3H2O→LipaseGlycerol+3(FattyAcids)Triglyceride + 3H_{2}O \xrightarrow{Lipase} Glycerol + 3(Fatty Acids).

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Absorption occurs primarily in the small intestine. The inner surface is covered in Villi and Microvilli to maximize the surface area-to-volume ratio (SA:VSA:V), facilitating faster diffusion and active transport.

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Bile is produced in the liver, stored in the gallbladder, and acts in the duodenum. It performs two roles: Emulsification (increasing lipid surface area) and neutralization of stomach HClHCl to create an alkaline environment (pH≈8.0pH \approx 8.0).

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Egestion is the discharge of undigested and unabsorbed food as feces through the anus. This is distinct from excretion, which is the removal of metabolic waste (like CO2CO_{2} or urea).

📐Formulae

Starch+nH2O→Amylasen(Maltose)Starch + nH_{2}O \xrightarrow{\text{Amylase}} n(Maltose)

Proteins+H2O→ProteaseAminoAcidsProteins + H_{2}O \xrightarrow{\text{Protease}} Amino Acids

Triglyceride+3H2O→LipaseGlycerol+3 Fatty AcidsTriglyceride + 3H_{2}O \xrightarrow{\text{Lipase}} Glycerol + 3 \text{ Fatty Acids}

BMI=mass (kg)[height (m)]2BMI = \frac{mass\ (kg)}{[height\ (m)]^2}

Rate of Digestion=ΔMassΔt\text{Rate of Digestion} = \frac{\Delta \text{Mass}}{\Delta t}

💡Examples

Problem 1:

During an experiment, 20 g20\text{ g} of starch is placed in a beaker with amylase. After 4 minutes4\text{ minutes}, all the starch has been converted to maltose. Calculate the rate of the enzymatic reaction in g/min\text{g/min}.

Solution:

Rate=Mass of StarchTime=20 g4 min=5 g/minRate = \frac{\text{Mass of Starch}}{\text{Time}} = \frac{20\text{ g}}{4\text{ min}} = 5\text{ g/min}

Explanation:

The rate of digestion is found by dividing the total change in mass of the substrate by the time elapsed.

Problem 2:

A person has a body mass of 75 kg75\text{ kg} and a height of 1.8 m1.8\text{ m}. Calculate their Body Mass Index (BMIBMI).

Solution:

BMI=751.82=753.24≈23.15 kg/m2BMI = \frac{75}{1.8^2} = \frac{75}{3.24} \approx 23.15\text{ kg/m}^2

Explanation:

The BMIBMI is calculated by dividing the mass in kilograms by the square of the height in meters. A value of 23.1523.15 falls within the healthy weight range.

Problem 3:

Explain the pHpH transition of food as it moves from the stomach to the small intestine.

Solution:

In the stomach, the environment is highly acidic (pH≈1.5 to 2.0pH \approx 1.5 \text{ to } 2.0) due to HClHCl. As food (chyme) enters the small intestine, Bile and pancreatic juices (containing sodium bicarbonate) neutralize the acid, raising the pHpH to approximately 8.08.0.

Explanation:

This pHpH change is necessary because stomach enzymes (Pepsin) require low pHpH, while intestinal enzymes (Trypsin, Lipase) require an alkaline pHpH to function optimally.

Digestion, Absorption, and Egestion Grade 9 Notes & Examples