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Chemical Reactions - Collision Theory

Grade 9IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Collision Theory states that for a chemical reaction to occur, the reacting particles must collide with each other with sufficient energy and the correct orientation.

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An Effective Collision is a collision that results in a reaction. This requires the particles to possess a minimum amount of energy known as the Activation Energy (EaE_a).

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Activation Energy (EaE_a): The minimum energy required by colliding particles to break existing bonds and initiate a chemical reaction.

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Factors affecting Reaction Rate: 1. Concentration: Higher concentration increases the number of particles per unit volume, leading to more frequent collisions. 2. Pressure (for gases): Increasing pressure crowds gas particles together, increasing collision frequency.

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Temperature: Increasing temperature increases the average kinetic energy of particles. This leads to more frequent collisions and, more importantly, a higher proportion of particles having energy ≥Ea\ge E_a.

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Surface Area: For solid reactants, increasing surface area (by grinding or crushing) exposes more particles to the other reactant, increasing the frequency of collisions.

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Catalysts: A catalyst increases the rate of reaction by providing an alternative reaction pathway with a lower activation energy (EaE_a), allowing more collisions to be successful without the catalyst being consumed.

📐Formulae

Rate of Reaction=Change in concentration or massTime taken\text{Rate of Reaction} = \frac{\text{Change in concentration or mass}}{\text{Time taken}}

Average Rate=Δ[P]Δt\text{Average Rate} = \frac{\Delta [P]}{\Delta t}

Frequency of Collisions∝Concentration×Velocity\text{Frequency of Collisions} \propto \text{Concentration} \times \text{Velocity}

💡Examples

Problem 1:

In an experiment, 5.0 g5.0\text{ g} of Calcium Carbonate (CaCO3CaCO_3) reacts with excess Hydrochloric Acid (HClHCl). After 40 seconds40\text{ seconds}, 2.0 g2.0\text{ g} of the solid remains. Calculate the average rate of reaction in g/s\text{g/s}.

Solution:

Mass of reactant used=5.0 g−2.0 g=3.0 g\text{Mass of reactant used} = 5.0\text{ g} - 2.0\text{ g} = 3.0\text{ g} Rate=3.0 g40 s=0.075 g/s\text{Rate} = \frac{3.0\text{ g}}{40\text{ s}} = 0.075\text{ g/s}

Explanation:

The rate of reaction is calculated by dividing the change in mass of the reactant by the time elapsed. Since 3.0 g3.0\text{ g} of CaCO3CaCO_3 was consumed in 40 seconds40\text{ seconds}, the rate is 0.075 grams per second0.075\text{ grams per second}.

Problem 2:

Explain, using collision theory, why a 1.0 M1.0\text{ M} solution of HClHCl reacts faster with Zinc than a 0.5 M0.5\text{ M} solution of HClHCl.

Solution:

Higher concentration means more H+H^+ ions per unit volume →\rightarrow Higher frequency of collisions →\rightarrow Higher rate of reaction.

Explanation:

In a 1.0 M1.0\text{ M} solution, the density of particles is higher compared to a 0.5 M0.5\text{ M} solution. According to collision theory, more particles in the same space lead to a higher probability of collisions per second, thus increasing the reaction rate.