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Atomic Structure - Transition Elements and Rare Earth Metals

Grade 9IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Transition elements are metallic elements found in Groups 3 to 12 of the Periodic Table, characterized by the filling of the dd subshell. Their general electron configuration is represented as (n−1)d1−10ns1−2(n-1)d^{1-10} ns^{1-2}.

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Transition metals exhibit variable oxidation states. For example, Iron can exist as Fe2+Fe^{2+} or Fe3+Fe^{3+} because the energy levels of the 4s4s and 3d3d orbitals are very close, allowing electrons from both to be involved in bonding.

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A defining characteristic of transition elements is the formation of colored compounds. This occurs due to d−dd-d transitions, where electrons absorb specific frequencies of light to move between split dd-orbital energy levels.

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Many transition metals and their compounds act as efficient catalysts. Examples include Iron (FeFe) in the Haber process for ammonia synthesis and Vanadium(V) oxide (V2O5V_2O_5) in the Contact process.

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Transition elements typically have high melting points, high densities, and high boiling points compared to Group 1 and 2 metals due to the involvement of dd electrons in metallic bonding.

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Rare Earth Metals consist of the Lanthanide series (atomic numbers 5757 to 7171) and the Actinide series (atomic numbers 8989 to 103103). These are often referred to as the ff-block elements.

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Lanthanides are known for their high magnetic susceptibility and are widely used in high-tech devices, lasers, and strong permanent magnets (e.g., Neodymium magnets).

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Actinides are all radioactive. The series includes naturally occurring elements like Uranium (UU) and Thorium (ThTh), as well as synthetic transuranium elements.

📐Formulae

[NobleGas](n−1)d1−10ns1−2[Noble Gas] (n-1)d^{1-10} ns^{1-2}

Zeff=Z−SZ_{eff} = Z - S

Number of neutrons=Mass Number(A)−Atomic Number(Z)\text{Number of neutrons} = \text{Mass Number} (A) - \text{Atomic Number} (Z)

💡Examples

Problem 1:

Determine the electronic configuration of Chromium (CrCr) with atomic number Z=24Z = 24. Why is its configuration unique?

Solution:

The electronic configuration of Chromium is [Ar]3d54s1[Ar] 3d^5 4s^1.

Explanation:

Expected configuration would be [Ar]3d44s2[Ar] 3d^4 4s^2. However, a half-filled dd subshell (d5d^5) and a half-filled ss subshell (s1s^1) provide extra stability due to symmetrical distribution of electrons and exchange energy. This makes [Ar]3d54s1[Ar] 3d^5 4s^1 the preferred state.

Problem 2:

Calculate the number of unpaired electrons in a Fe3+Fe^{3+} ion (Z=26Z = 26).

Solution:

Fe=[Ar]3d64s2Fe = [Ar] 3d^6 4s^2 Fe3+=[Ar]3d5Fe^{3+} = [Ar] 3d^5 Number of unpaired electrons = 55.

Explanation:

When forming a Fe3+Fe^{3+} ion, the atom loses two electrons from the 4s4s orbital first, and then one from the 3d3d orbital. The 3d53d^5 configuration results in five orbitals each containing one electron (according to Hund's Rule), meaning there are 55 unpaired electrons.

Problem 3:

A rare earth metal isotope has a mass number of 140140 and contains 5858 protons. Identify the element and calculate the number of neutrons.

Solution:

Neutrons=A−Z\text{Neutrons} = A - Z Neutrons=140−58=82\text{Neutrons} = 140 - 58 = 82

Explanation:

The atomic number Z=58Z = 58 corresponds to Cerium (CeCe), which is the first element of the Lanthanide series. By subtracting the atomic number (protons) from the mass number, we find there are 8282 neutrons.