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Atomic Structure - Group 7 Halogens and Displacement Reactions

Grade 9IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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The Halogens are the elements in Group 7 of the Periodic Table, including Fluorine (FF), Chlorine (ClCl), Bromine (BrBr), Iodine (II), and Astatine (AtAt).

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Atomic structure: All halogens have 7 electrons in their outermost shell, giving them a valency of 1−1- as they need to gain one electron to achieve a stable noble gas configuration.

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Physical Trends: Down the group, the atomic radius increases and the relative molecular mass increases. This leads to stronger intermolecular forces, resulting in higher melting and boiling points (F2F_2 and Cl2Cl_2 are gases, Br2Br_2 is a liquid, I2I_2 is a solid).

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Chemical Trends: Reactivity decreases down the group. As the atom gets larger, the outer shell is further from the nucleus and more shielded by inner electrons, making it harder for the nucleus to attract and capture an incoming electron.

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Displacement Reactions: A more reactive halogen will displace a less reactive halogen from its halide salt solution. For example, Chlorine can displace Bromine from Potassium Bromide.

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Redox Nature: Displacement reactions are redox reactions. The more reactive halogen acts as an oxidising agent by gaining electrons (reduction: X2+2e−→2X−X_2 + 2e^- \rightarrow 2X^-), while the halide ion is oxidised (oxidation: 2Y−→Y2+2e−2Y^- \rightarrow Y_2 + 2e^-).

📐Formulae

X2+2MY→2MX+Y2X_2 + 2MY \rightarrow 2MX + Y_2

Cl2(aq)+2Br−(aq)→2Cl−(aq)+Br2(aq)Cl_2(aq) + 2Br^-(aq) \rightarrow 2Cl^-(aq) + Br_2(aq)

Br2+2e−→2Br−Br_2 + 2e^- \rightarrow 2Br^-

2I−→I2+2e−2I^- \rightarrow I_2 + 2e^-

💡Examples

Problem 1:

Predict the observation and write the ionic equation when Chlorine water (Cl2Cl_2) is added to a solution of Potassium Iodide (KIKI).

Solution:

Observation: The colorless solution turns dark brown due to the formation of Iodine (I2I_2). Ionic Equation: Cl2(aq)+2I−(aq)→2Cl−(aq)+I2(aq)Cl_2(aq) + 2I^-(aq) \rightarrow 2Cl^-(aq) + I_2(aq)

Explanation:

Chlorine is higher in Group 7 than Iodine, making it more reactive. Chlorine atoms attract electrons more strongly than Iodine atoms, so Chlorine displaces the Iodide ions. The I−I^- ions lose electrons to become I2I_2 molecules, which color the solution.

Problem 2:

Explain why no reaction occurs when Bromine (Br2Br_2) is added to Sodium Chloride (NaClNaCl) solution.

Solution:

No reaction occurs because Bromine is less reactive than Chlorine.

Explanation:

In Group 7, reactivity decreases down the group (Cl>Br>ICl > Br > I). Since Bromine is below Chlorine, it is a weaker oxidising agent and cannot remove electrons from the stable Chloride (Cl−Cl^-) ions.

Problem 3:

Write the half-equation for the reduction of Fluorine gas.

Solution:

F2+2e−→2F−F_2 + 2e^- \rightarrow 2F^-

Explanation:

Reduction is the gain of electrons. A Fluorine molecule (F2F_2) gains two electrons to form two Fluoride ions (F−F^-), achieving a full outer shell.