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Structure of the Atom - Rediscovering the Roots of Atomic Theory

Grade 9CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Dalton's Atomic Theory originally suggested that atoms were indivisible; however, the discovery of subatomic particles like electrons (e−e^-) and protons (p+p^+) led to its revision.

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J.J. Thomson's Model (Plum Pudding Model) proposed that an atom consists of a positively charged sphere with electrons embedded in it, ensuring the atom is electrically neutral.

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Rutherford's α\alpha-particle scattering experiment revealed that most of the atom's space is empty and that the mass is concentrated in a tiny, positively charged center called the nucleus.

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Bohr's Model of the Atom introduced discrete orbits or shells (K,L,M,NK, L, M, N) where electrons revolve without radiating energy.

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The Atomic Number (ZZ) is the total number of protons in the nucleus of an atom. For a neutral atom, Z=number of protons=number of electronsZ = \text{number of protons} = \text{number of electrons}.

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The Mass Number (AA) is the sum of the total number of protons and neutrons (collectively called nucleons) in the nucleus: A=Z+nA = Z + n.

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Valency is the combining capacity of an atom, determined by the number of electrons in its outermost shell. For atoms with 11 to 44 valence electrons, valency equals the number of valence electrons; for those with 55 to 77, it is often calculated as 8−valence electrons8 - \text{valence electrons}.

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Isotopes are atoms of the same element with the same atomic number but different mass numbers (e.g., 11H{}_{1}^{1}\text{H}, 12H{}_{1}^{2}\text{H}, and 13H{}_{1}^{3}\text{H}).

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Isobars are atoms of different elements with the same mass number but different atomic numbers (e.g., 1840Ar{}_{18}^{40}\text{Ar} and 2040Ca{}_{20}^{40}\text{Ca}).

📐Formulae

A=Z+nA = Z + n

Number of Neutrons(n)=A−Z\text{Number of Neutrons} (n) = A - Z

Maximum electrons in nth shell=2n2\text{Maximum electrons in } n^{th} \text{ shell} = 2n^2

Average Atomic Mass=(Mass1×%1)+(Mass2×%2)100\text{Average Atomic Mass} = \frac{(\text{Mass}_1 \times \%_1) + (\text{Mass}_2 \times \%_2)}{100}

💡Examples

Problem 1:

Calculate the number of neutrons in an atom of Phosphorus (1531P{}_{15}^{31}\text{P}).

Solution:

n=A−Z=31−15=16n = A - Z = 31 - 15 = 16

Explanation:

The mass number AA is 3131 and the atomic number ZZ is 1515. Subtracting the number of protons from the mass number gives 1616 neutrons.

Problem 2:

Determine the electronic configuration and valency of Magnesium (Z=12Z = 12).

Solution:

Electronic Configuration: K=2,L=8,M=2K=2, L=8, M=2. Valency: 22.

Explanation:

Using the 2n22n^2 rule, the first shell holds 22, the second 88, leaving 22 electrons in the MM shell. Since it has 22 electrons in the outermost shell, its valency is 22.

Problem 3:

An element exists as two isotopes with masses 35u35\text{u} (75%75\%) and 37u37\text{u} (25%25\%). Calculate the average atomic mass.

Solution:

Avg Mass=(35×75)+(37×25)100=2625+925100=35.5u\text{Avg Mass} = \frac{(35 \times 75) + (37 \times 25)}{100} = \frac{2625 + 925}{100} = 35.5\text{u}

Explanation:

The average atomic mass is the weighted average based on the natural abundance of isotopes.

Problem 4:

Calculate the difference in the number of nucleons between Carbon-12 and Carbon-14.

Solution:

14−122\begin{array}{r} 14 \\ - 12 \\ \hline 2 \end{array}

Explanation:

Nucleons represent the mass number. Carbon-14 has 1414 nucleons and Carbon-12 has 1212 nucleons, resulting in a difference of 22 neutrons.