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Structure of the Atom - A Deeper Look into Atomic Structure

Grade 9CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Subatomic Particles: Atoms consist of protons (p+p^+), neutrons (n0n^0), and electrons (e−e^-). Protons and neutrons reside in the nucleus, while electrons revolve around it.

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Thomson's Model: Proposed that an atom consists of a positively charged sphere with electrons embedded in it, like seeds in a watermelon.

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Rutherford's α\alpha-particle Scattering: Showed that most of the atom is empty space and that there is a small, dense, positively charged nucleus at the center. The radius of the nucleus is about 10510^5 times smaller than the radius of the atom.

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Bohr's Model: Electrons revolve in discrete orbits called shells (K,L,M,NK, L, M, N). While revolving in these orbits, electrons do not radiate energy.

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Electronic Configuration: The distribution of electrons is governed by the Bohr-Bury scheme. The maximum number of electrons in a shell is given by 2n22n^2, where nn is the orbit number.

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Valency: The combining capacity of an atom, determined by the number of electrons in its outermost (valence) shell. Atoms react to achieve a stable octet (88 electrons in the valence shell).

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Atomic Number (ZZ): The total number of protons in the nucleus of an atom.

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Mass Number (AA): The sum of the total number of protons and neutrons in the nucleus of an atom.

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Isotopes: Atoms of the same element having the same atomic number but different mass numbers (e.g., 11H^{1}_{1}H, 12H^{2}_{1}H, 13H^{3}_{1}H).

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Isobars: Atoms of different elements with the same mass number but different atomic numbers (e.g., 1840Ar^{40}_{18}Ar and 2040Ca^{40}_{20}Ca).

📐Formulae

Z=pZ = p

A=p+nA = p + n

Maximum electrons in a shell=2n2\text{Maximum electrons in a shell} = 2n^2

Number of neutrons (n)=A−Z\text{Number of neutrons (n)} = A - Z

Average Atomic Mass=(Mass1×%1)+(Mass2×%2)100\text{Average Atomic Mass} = \frac{(\text{Mass}_1 \times \%_1) + (\text{Mass}_2 \times \%_2)}{100}

💡Examples

Problem 1:

An atom of an element has an atomic number 1111 and a mass number 2323. Calculate the number of neutrons in the atom.

Solution:

Given: A=23A = 23, Z=11Z = 11. Number of neutrons n=A−Zn = A - Z.

Explanation:

Subtract the atomic number from the mass number: 23−1112\begin{array}{r} 23 \\ - 11 \\ \hline 12 \end{array} The number of neutrons is 1212.

Problem 2:

Chlorine occurs in nature in two isotopic forms with masses 35u35u and 37u37u in the ratio of 3:13:1. Calculate the average atomic mass of Chlorine.

Solution:

Avg. Mass =(35×75100)+(37×25100)=1054+374=1424=35.5u= (35 \times \frac{75}{100}) + (37 \times \frac{25}{100}) = \frac{105}{4} + \frac{37}{4} = \frac{142}{4} = 35.5u

Explanation:

The average atomic mass is the weighted average of the isotopes based on their natural abundance.

Problem 3:

Write the electronic configuration and valency of Magnesium (Z=12Z=12).

Solution:

Distribution: K=2,L=8,M=2K=2, L=8, M=2. Valency =2= 2.

Explanation:

Magnesium has 1212 electrons. KK shell takes 2(1)2=22(1)^2=2, LL shell takes 2(2)2=82(2)^2=8. The remaining 22 go to the MM shell. Since it has 22 valence electrons, it tends to lose them to achieve stability, so its valency is 22.