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Cell - Explain role of mitosis and meiosis in growth, repair, and variation

Grade 9CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Cell division is the process by which a parent cell divides into two or more daughter cells. It is essential for growth, repair, and reproduction in living organisms.

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Mitosis (Equational Division): A single parent cell divides to produce two genetically identical daughter cells. The chromosome number remains the same (2n→2n2n \rightarrow 2n).

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Role of Mitosis in Growth: It increases the number of cells in an organism, allowing a single-celled zygote to develop into a complex multicellular body.

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Role of Mitosis in Repair: It replaces old, dead, or damaged cells. For example, the healing of a wound or the constant replacement of red blood cells and skin cells.

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Meiosis (Reduction Division): A parent cell undergoes two successive divisions to produce four daughter cells (gametes), each having half the number of chromosomes (2n→n2n \rightarrow n).

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Role of Meiosis in Variation: During meiosis, 'crossing over' occurs where genetic material is exchanged between homologous chromosomes. This leads to genetic recombination and variation in the offspring.

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Role of Meiosis in Reproduction: It ensures that the chromosome number of a species remains constant across generations by producing haploid gametes (nn) that fuse during fertilization to form a diploid zygote (2n2n).

📐Formulae

Chromosome Number in Mitosis: 2n→2n\text{Chromosome Number in Mitosis: } 2n \rightarrow 2n

Chromosome Number in Meiosis: 2n→n\text{Chromosome Number in Meiosis: } 2n \rightarrow n

Total daughter cells after n mitotic divisions=2n\text{Total daughter cells after } n \text{ mitotic divisions} = 2^n

Total daughter cells after 1 meiotic cycle=4\text{Total daughter cells after 1 meiotic cycle} = 4

💡Examples

Problem 1:

If a mother cell has 2n=462n = 46 chromosomes, calculate the number of chromosomes in the daughter cells after (a) Mitosis and (b) Meiosis.

Solution:

(a) After mitosis: 4646 chromosomes. (b) After meiosis: 2323 chromosomes.

Explanation:

In mitosis, the chromosome count is conserved (2n2n), so 4646 remains 4646. In meiosis, the count is halved (nn), so 462=23\frac{46}{2} = 23.

Problem 2:

A tissue sample undergoes 44 successive mitotic divisions. Calculate the total number of cells produced starting from a single cell.

Solution:

Total cells = 24=162^4 = 16.

Explanation:

Using the formula for mitotic cell count: 2n=2×2×2×2=162^n = 2 \times 2 \times 2 \times 2 = 16