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Chemistry: Atomic Structure, Bonding, and Periodicity - Metals, Non-metals, Metalloids, Alloys, and Periodic Families

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Atomic Structure: Atoms consist of a central nucleus containing protons (p+p^+) and neutrons (n0n^0), surrounded by electrons (e−e^-) in energy levels or shells. The number of protons defines the Atomic Number (ZZ).

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Electronic Configuration: Electrons are arranged in shells following the 2n22n^2 rule. For Grade 8, we focus on the first 20 elements with the configuration pattern 2,8,8,22, 8, 8, 2.

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Metals: Located on the left of the Periodic Table. They are typically lustrous, malleable, ductile, and good conductors of heat and electricity. They tend to lose electrons to form positive ions (cations).

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Non-metals: Located on the right of the Periodic Table. They are generally brittle in solid form, poor conductors, and tend to gain electrons to form negative ions (anions).

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Metalloids: Elements found along the 'staircase' (e.g., Silicon SiSi, Germanium GeGe) that possess properties intermediate between metals and non-metals.

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Periodic Families: Group 1 (Alkali Metals) are highly reactive with 1 valence electron; Group 17 (Halogens) are highly reactive non-metals with 7 valence electrons; Group 18 (Noble Gases) are inert with full outer shells.

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Alloys: A homogeneous mixture of two or more metals, or a metal and a non-metal (e.g., Steel is Fe+CFe + C). Alloys are often harder and more resistant to corrosion than pure metals.

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Bonding: Ionic bonding involves the transfer of electrons from a metal to a non-metal, while Covalent bonding involves the sharing of electron pairs between non-metals.

📐Formulae

A=Z+N (where A is Mass Number, Z is Atomic Number, and N is Number of Neutrons)A = Z + N \text{ (where } A \text{ is Mass Number, } Z \text{ is Atomic Number, and } N \text{ is Number of Neutrons)}

Net Charge=(number of protons)−(number of electrons)\text{Net Charge} = (\text{number of protons}) - (\text{number of electrons})

2n2 (Maximum electrons in shell n)2n^2 \text{ (Maximum electrons in shell } n\text{)}

4Li+O2→2Li2O (Oxidation of an Alkali Metal)4Li + O_2 \rightarrow 2Li_2O \text{ (Oxidation of an Alkali Metal)}

💡Examples

Problem 1:

An atom of Magnesium has an atomic number Z=12Z = 12 and a mass number A=24A = 24. Determine the number of protons, neutrons, and electrons in a Mg2+Mg^{2+} ion.

Solution:

Protons = 1212, Neutrons = 1212, Electrons = 1010.

Explanation:

The atomic number 1212 means there are 1212 protons. Neutrons are calculated as A−Z=24−12=12A - Z = 24 - 12 = 12. A neutral atom would have 1212 electrons, but a 2+2+ charge indicates the loss of 22 electrons: 12−2=1012 - 2 = 10.

Problem 2:

Explain why Bronze is used for making statues instead of pure Copper (CuCu).

Solution:

Bronze is an alloy consisting of approximately 88%88\% Copper and 12%12\% Tin (SnSn).

Explanation:

Pure copper is relatively soft. By adding tin to form the alloy Bronze, the different-sized atoms disrupt the regular layers of atoms, making it much harder and more resistant to corrosion.

Problem 3:

Identify the period and group for an element with the electronic configuration 2,8,72, 8, 7.

Solution:

Period: 33, Group: 1717 (or 7A7A).

Explanation:

The number of shells (three: 2,8,72, 8, 7) determines the Period. The number of valence electrons (77) determines the Group. This element is Chlorine (ClCl).