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Chemistry: Atomic Structure, Bonding, and Periodicity - Atomic Number, Mass Number, Isotopes, and Electronic Configuration

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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The atom consists of three primary subatomic particles: protons (p+p^+), neutrons (n0n^0), and electrons (e−e^-). Protons and neutrons are located in the central nucleus, while electrons orbit in shells.

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The Atomic Number (ZZ) represents the number of protons in an atom. Since atoms are electrically neutral, the number of protons equals the number of electrons.

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The Mass Number (AA) is the total number of protons and neutrons in the nucleus of an atom.

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Isotopes are atoms of the same element that have the same number of protons (Atomic Number) but different numbers of neutrons (Mass Number). For example, 612C^{12}_{6}C and 614C^{14}_{6}C are isotopes of Carbon.

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Electronic Configuration describes the distribution of electrons in specific energy levels or shells. For the first 20 elements, the shells follow a maximum capacity of 2,8,8,22, 8, 8, 2.

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The Valence Shell is the outermost electron shell. The number of electrons in this shell determines the chemical properties and reactivity of the element.

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Standard Atomic Notation is written as ZAX^{A}_{Z}X, where XX is the chemical symbol, AA is the mass number, and ZZ is the atomic number.

📐Formulae

A=Z+NA = Z + N

N=A−ZN = A - Z

Number of electrons (neutral atom)=Z\text{Number of electrons (neutral atom)} = Z

Maximum electrons in shell n=2n2\text{Maximum electrons in shell } n = 2n^2

💡Examples

Problem 1:

An atom of Sodium (NaNa) has an atomic number Z=11Z = 11 and a mass number A=23A = 23. Calculate the number of protons, neutrons, and electrons, and write its electronic configuration.

Solution:

Protons: 1111, Electrons: 1111, Neutrons: 23−11=1223 - 11 = 12. Electronic Configuration: 2,8,12, 8, 1.

Explanation:

Since Z=11Z = 11, there are 1111 protons and 1111 electrons. Neutrons are found using A−Z=23−11=12A - Z = 23 - 11 = 12. The electrons fill the shells starting from the innermost: 22 in the first shell, 88 in the second, and the remaining 11 in the third shell.

Problem 2:

Calculate the number of neutrons in the isotope of Chlorine 1737Cl^{37}_{17}Cl.

Solution:

37−17=2037 - 17 = 20 neutrons.

Explanation:

In the notation ZAX^{A}_{Z}X, A=37A = 37 and Z=17Z = 17. The number of neutrons NN is calculated as N=A−Z=37−17=20N = A - Z = 37 - 17 = 20.

Problem 3:

Determine the electronic configuration of Calcium (Z=20Z = 20).

Solution:

2,8,8,22, 8, 8, 2

Explanation:

With 2020 electrons, the first shell takes 22, the second takes 88, the third takes 88, and the final 22 electrons occupy the fourth shell to maintain stability for early elements.