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How Nature Works in Harmony - What Are the Benefits of an Ecosystem?

Grade 8CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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An ecosystem is a self-sustaining unit where biotic components (plants, animals, microorganisms) interact with abiotic components (air, water, soil, sunlight).

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Biotic components are classified into Producers (autotrophs), Consumers (heterotrophs), and Decomposers (saprotrophs).

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Producers, such as green plants, convert solar energy into chemical energy through the process of photosynthesis: 6CO2+6H2O→SunlightC6H12O6+6O26CO_2 + 6H_2O \xrightarrow{\text{Sunlight}} C_6H_{12}O_6 + 6O_2.

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Energy flow in an ecosystem is unidirectional, moving from producers to various levels of consumers.

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The 10% Law states that only 10%10\% of the energy available at one trophic level is transferred to the next level, while 90%90\% is lost as heat or used for metabolic processes.

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Decomposers play a vital role in nutrient cycling by breaking down dead organic matter and returning minerals to the soil.

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Ecosystem services include Provisioning (food, water, timber), Regulating (climate control, water purification), Supporting (soil formation, nutrient cycling), and Cultural benefits (recreation, spiritual value).

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Biodiversity ensures ecosystem stability; the more complex the food web, the more resilient the ecosystem is to environmental changes.

📐Formulae

6CO2+6H2O+light energy→C6H12O6+6O26CO_2 + 6H_2O + \text{light energy} \rightarrow C_6H_{12}O_6 + 6O_2

En+1=10100×EnE_{n+1} = \frac{10}{100} \times E_n

Energy Efficiency=(Energy at Trophic Level n+1Energy at Trophic Level n)×100\text{Energy Efficiency} = \left( \frac{\text{Energy at Trophic Level } n+1}{\text{Energy at Trophic Level } n} \right) \times 100

💡Examples

Problem 1:

In a simple food chain (Grass →\rightarrow Grasshopper →\rightarrow Frog), if the Grass produces 5000 J5000\text{ J} of energy, calculate the energy available to the Frog using the 10% Law.

Solution:

Energy at Producer level (Grass) = 5000 J5000\text{ J}. Energy at Primary Consumer (Grasshopper) = 10%10\% of 5000=10100×5000=500 J5000 = \frac{10}{100} \times 5000 = 500\text{ J}. Energy at Secondary Consumer (Frog) = 10%10\% of 500=10100×500=50 J500 = \frac{10}{100} \times 500 = 50\text{ J}.

Explanation:

According to the 10% Law, each successive trophic level receives only 1/10th1/10^{th} of the energy from the level below it.

Problem 2:

Calculate the total biomass remaining if a forest ecosystem starts with 80,000,000 kg80,000,000\text{ kg} of producer biomass and loses 34,567,892 kg34,567,892\text{ kg} due to a localized drought.

Solution:

80000000−3456789245432108\begin{array}{r} 80000000 \\ -34567892 \\ \hline 45432108 \end{array} The remaining biomass is 45,432,108 kg45,432,108\text{ kg}.

Explanation:

This subtraction represents the net change in available biotic resources within the ecosystem after an environmental stressor.

What Are the Benefits of an Ecosystem? Class 8 Notes & Examples