krit.club logo

Changes Around Us: Physical and Chemical - Some Other Processes Involving Chemical Changes

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

•

Rusting of Iron: It is a chemical change where iron reacts with oxygen and moisture (H2OH_2O) from the air to form a reddish-brown substance called rust (Hydrated Iron Oxide). Both oxygen and water are essential for rusting.

•

Prevention of Rusting: Rusting can be prevented by cutting off the contact of iron with air and moisture. Methods include painting, applying grease/oil, and Galvanization (the process of depositing a layer of zinc on iron).

•

Reaction between Copper Sulphate and Iron: When an iron nail is placed in a blue-colored Copper Sulphate (CuSO4CuSO_4) solution, it turns green due to the formation of Iron Sulphate (FeSO4FeSO_4). A brown deposit of copper is seen on the nail. This is a displacement reaction.

•

Reaction between Vinegar and Baking Soda: Vinegar (Acetic acid) reacts with Baking Soda (Sodium Hydrogen Carbonate) to produce Carbon Dioxide (CO2CO_2) gas and other substances. The presence of CO2CO_2 is confirmed by passing it through lime water.

•

Lime Water Test: When CO2CO_2 gas is passed through lime water (Ca(OH)2Ca(OH)_2), it turns milky due to the formation of insoluble Calcium Carbonate (CaCO3CaCO_3).

•

Burning of Magnesium Ribbon: Burning magnesium in air is a chemical change. It reacts with oxygen to form a white powdery ash called Magnesium Oxide (MgOMgO). When dissolved in water, it forms Magnesium Hydroxide (Mg(OH)2Mg(OH)_2), which is basic.

•

Crystallization: It is a process used to obtain large crystals of pure substances from their solutions. Although it involves a change in state/form, it is considered a physical change because no new chemical substance is formed.

📐Formulae

4Fe+3O2+2xH2O→2Fe2O3⋅xH2O (Rusting)4Fe + 3O_2 + 2xH_2O \rightarrow 2Fe_2O_3 \cdot xH_2O \text{ (Rusting)}

2Mg+O2→2MgO (Burning of Magnesium)2Mg + O_2 \rightarrow 2MgO \text{ (Burning of Magnesium)}

MgO+H2O→Mg(OH)2 (Magnesium Hydroxide formation)MgO + H_2O \rightarrow Mg(OH)_2 \text{ (Magnesium Hydroxide formation)}

CuSO4 (Blue)+Fe→FeSO4 (Green)+Cu (Brown deposit)CuSO_4 \text{ (Blue)} + Fe \rightarrow FeSO_4 \text{ (Green)} + Cu \text{ (Brown deposit)}

CH3COOH+NaHCO3→CH3COONa+H2O+CO2↑CH_3COOH + NaHCO_3 \rightarrow CH_3COONa + H_2O + CO_2 \uparrow

Ca(OH)2+CO2→CaCO3↓+H2O (Lime water turning milky)Ca(OH)_2 + CO_2 \rightarrow CaCO_3 \downarrow + H_2O \text{ (Lime water turning milky)}

💡Examples

Problem 1:

A student drops an iron nail into a blue solution of Copper Sulphate. After some time, the solution turns green. Explain the chemical change using an equation.

Solution:

The change is a chemical reaction where iron displaces copper from copper sulphate. The green color is due to the formation of Iron Sulphate (FeSO4FeSO_4).

Explanation:

The chemical equation is: Fe+CuSO4→FeSO4+CuFe + CuSO_4 \rightarrow FeSO_4 + Cu. The blue CuSO4CuSO_4 solution changes to green FeSO4FeSO_4, and brown copper is deposited on the iron nail.

Problem 2:

Explain why rusting is faster in coastal areas than in deserts.

Solution:

Rusting requires both oxygen and moisture (H2OH_2O). Coastal areas have high humidity (water vapor content in air), whereas deserts have dry air.

Explanation:

The presence of salt in coastal water also speeds up the process of rust formation. In a desert, the lack of moisture significantly slows down the reaction: 4Fe+3O2+2xH2O→2Fe2O3⋅xH2O4Fe + 3O_2 + 2xH_2O \rightarrow 2Fe_2O_3 \cdot xH_2O.

Problem 3:

What happens when Carbon Dioxide is passed through Lime Water? Provide the equation.

Solution:

The lime water turns milky because of the formation of Calcium Carbonate.

Explanation:

The reaction is: Ca(OH)2+CO2→CaCO3+H2OCa(OH)_2 + CO_2 \rightarrow CaCO_3 + H_2O. The CaCO3CaCO_3 is a white precipitate that makes the solution appear cloudy or milky.