krit.club logo

Changes Around Us: Physical and Chemical - Are All Changes Desirable?

Grade 7CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

•

Physical Change: A change in which a substance undergoes a change in its physical properties like shape, size, color, or state. It is generally reversible, and no new substance is formed. Example: Melting of ice (H2O(s)→H2O(l)H_2O(s) \rightarrow H_2O(l)).

•

Chemical Change: A change in which one or more new substances are formed. It is often irreversible and accompanied by heat/light release, gas production, or color change. Example: Burning of paper.

•

Rusting: When iron objects are exposed to oxygen and moisture (water vapor), they form a flaky brown substance called rust (Fe2O3⋅xH2OFe_2O_3 \cdot xH_2O).

•

Galvanization: The process of depositing a layer of zinc (ZnZn) on iron to prevent it from rusting.

•

Crystallization: A physical process used to obtain large crystals of pure substances from their solutions. Example: Obtaining pure Copper Sulphate (CuSO4CuSO_4) crystals.

•

Reaction of Vinegar and Baking Soda: Mixing vinegar (acetic acid) and baking soda (sodium hydrogen carbonate) produces Carbon dioxide (CO2CO_2), which turns lime water milky due to the formation of Calcium Carbonate (CaCO3CaCO_3).

•

Reaction of Iron with Copper Sulphate: When an iron nail is placed in blue Copper Sulphate solution, it turns green due to the formation of Iron Sulphate (FeSO4FeSO_4) and a brown deposit of Copper (CuCu) is seen.

•

Desirability of Changes: Changes can be classified as desirable (e.g., ripening of fruits, cooking of food) or undesirable (e.g., rusting of iron, spoiling of food) based on their utility to humans.

📐Formulae

4Fe+3O2+2xH2O→2Fe2O3⋅xH2O (Rust)4Fe + 3O_2 + 2xH_2O \rightarrow 2Fe_2O_3 \cdot xH_2O \text{ (Rust)}

2Mg+O2→2MgO (Magnesium Oxide)2Mg + O_2 \rightarrow 2MgO \text{ (Magnesium Oxide)}

MgO+H2O→Mg(OH)2 (Magnesium Hydroxide)MgO + H_2O \rightarrow Mg(OH)_2 \text{ (Magnesium Hydroxide)}

CuSO4 (Blue)+Fe→FeSO4 (Green)+Cu (Brown deposit)CuSO_4 \text{ (Blue)} + Fe \rightarrow FeSO_4 \text{ (Green)} + Cu \text{ (Brown deposit)}

Ca(OH)2+CO2→CaCO3↓+H2O (Milkiness test)Ca(OH)_2 + CO_2 \rightarrow CaCO_3 \downarrow + H_2O \text{ (Milkiness test)}

CH3COOH+NaHCO3→CH3COONa+H2O+CO2↑CH_3COOH + NaHCO_3 \rightarrow CH_3COONa + H_2O + CO_2 \uparrow

💡Examples

Problem 1:

What happens when a piece of Magnesium (MgMg) ribbon is burnt in air and the resulting ash is dissolved in water? Test the nature of the solution.

Solution:

2Mg+O2→2MgO2Mg + O_2 \rightarrow 2MgO followed by MgO+H2O→Mg(OH)2MgO + H_2O \rightarrow Mg(OH)_2.

Explanation:

Burning magnesium produces Magnesium Oxide (MgOMgO). When dissolved in water, it forms Magnesium Hydroxide (Mg(OH)2Mg(OH)_2), which is basic in nature and turns red litmus paper blue.

Problem 2:

Explain why rusting of iron objects is faster in coastal areas than in deserts.

Solution:

Rusting requires both oxygen (O2O_2) and moisture (H2OH_2O).

Explanation:

Coastal areas have high humidity (more water vapor in the air) compared to deserts. The presence of salt in coastal water also speeds up the process of rusting, making it faster than in dry desert conditions.

Problem 3:

When Carbon dioxide (CO2CO_2) is passed through lime water, why does it turn milky?

Solution:

Ca(OH)2+CO2→CaCO3+H2OCa(OH)_2 + CO_2 \rightarrow CaCO_3 + H_2O

Explanation:

The reaction between lime water (Calcium hydroxide) and Carbon dioxide produces Calcium Carbonate (CaCO3CaCO_3), which is an insoluble white precipitate. This suspension of fine particles makes the lime water appear milky.