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Energy—How Things Work - Sources of Energy: Fuel and Electricity

Grade 5CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Energy is defined as the capacity or ability to do work. It is measured in Joules (JJ).

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Fuel is a substance that releases energy, usually in the form of heat, when it is burned (combustion). Common examples include wood, coal, and LPG.

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Non-renewable Energy Sources are those that exist in limited quantities and take millions of years to form, such as fossil fuels (coal, petroleum, and natural gas).

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Renewable Energy Sources are inexhaustible and can be replenished naturally. Examples include Solar Energy (EsolarE_{solar}), Wind Energy (EwindE_{wind}), and Hydroelectric Energy (EhydroE_{hydro}).

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Electricity is a form of energy resulting from the flow of electric charge. It is often generated by converting mechanical energy into electrical energy using a generator.

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Energy Transformation: Energy can change from one form to another. For example, in an electric bulb, Electrical Energy →\rightarrow Light Energy + Heat Energy.

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Calorific Value is the amount of heat energy produced by the complete combustion of 11 kg of a fuel. It is expressed in kilojoules per kilogram (kJ/kgkJ/kg).

📐Formulae

Work Done=Force×Distance\text{Work Done} = \text{Force} \times \text{Distance}

Total Energy Consumption=Power (Watts)×Time (Hours)\text{Total Energy Consumption} = \text{Power (Watts)} \times \text{Time (Hours)}

Efficiency=Useful Energy OutputTotal Energy Input×100%\text{Efficiency} = \frac{\text{Useful Energy Output}}{\text{Total Energy Input}} \times 100\%

Total Cost of Fuel=Quantity of Fuel×Rate per Unit\text{Total Cost of Fuel} = \text{Quantity of Fuel} \times \text{Rate per Unit}

💡Examples

Problem 1:

A car uses 4545 litres of petrol for a long trip. If the cost of petrol is ₹102₹ 102 per litre, calculate the total expenditure on fuel.

Solution:

45×102=459045 \times 102 = 4590

Explanation:

To find the total cost, we multiply the quantity of fuel (4545 L) by the price per unit (₹102₹ 102). The total cost is ₹4,590₹ 4,590.

Problem 2:

A city power grid produced 90,000,00090,000,000 units of electricity. Due to a technical glitch, 28,456,71528,456,715 units were lost in transmission. Calculate the remaining units available for the city.

Solution:

90000000−2845671561543285\begin{array}{r} 90000000 \\ -28456715 \\ \hline 61543285 \end{array}

Explanation:

We subtract the lost units from the total produced units to find the net available electricity. The remaining units are 61,543,28561,543,285.

Problem 3:

Convert 55 Kilojoules (kJkJ) into Joules (JJ).

Solution:

5 kJ×1000=5000 J5 \text{ kJ} \times 1000 = 5000 \text{ J}

Explanation:

Since 1 kJ=1000 J1 \text{ kJ} = 1000 \text{ J}, we multiply the value in kJkJ by 10001000 to get the value in JJ.