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Periodic Classification of Elements - Explain modern periodic table trends and metallic vs non-metallic properties

Grade 10CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Modern Periodic Law: The physical and chemical properties of elements are a periodic function of their atomic number (ZZ). The atomic number represents the number of protons in the nucleus of an atom.

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Valency: The valency of an element is determined by the number of valence electrons present in the outermost shell. Across a period, valency increases from 11 to 44 and then decreases to 00. Down a group, valency remains constant because the number of valence electrons is the same.

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Atomic Size (Atomic Radius): It is the distance between the center of the nucleus and the outermost shell of an isolated atom. Across a period, atomic radius decreases because the effective nuclear charge (ZeffZ_{eff}) increases, pulling the electrons closer. Down a group, atomic radius increases because new shells are added, which outweighs the increase in nuclear charge.

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Metallic Character (Electropositivity): It is the tendency of an atom to lose electrons. Metals are found on the left side of the periodic table. Metallic character decreases across a period (due to increasing nuclear charge) and increases down a group (due to increasing atomic size and easier electron loss).

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Non-metallic Character (Electronegativity): It is the tendency of an atom to gain electrons. Non-metals are found on the right side. Non-metallic character increases across a period and decreases down a group.

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Nature of Oxides: Generally, oxides of metals are basic in nature (e.g., Na2ONa_2O, MgOMgO), while oxides of non-metals are acidic in nature (e.g., SO2SO_2, CO2CO_2).

📐Formulae

Z=p=e− (for a neutral atom)Z = p = e^- \text{ (for a neutral atom)}

Valency=Valence electrons (if ≤4)\text{Valency} = \text{Valence electrons (if } \le 4)

Valency=8−Valence electrons (if >4)\text{Valency} = 8 - \text{Valence electrons (if } > 4)

Effective Nuclear Charge (Zeff)∝1Atomic Radius\text{Effective Nuclear Charge } (Z_{eff}) \propto \frac{1}{\text{Atomic Radius}}

💡Examples

Problem 1:

An element XX has an atomic number of 1919. Identify its Period, Group, and determine if it is a metal or a non-metal.

Solution:

Electronic configuration of X(Z=19)X (Z=19) is 2,8,8,12, 8, 8, 1.

Explanation:

Since there are 44 shells, the Period is 44. Since there is 11 valence electron, the Group is 11. Because it can easily lose its 11 valence electron to achieve stability, it is a Metal (specifically an Alkali Metal).

Problem 2:

Arrange the following elements in increasing order of their atomic radii: Li,Be,F,NLi, Be, F, N.

Solution:

F<N<Be<LiF < N < Be < Li

Explanation:

These elements belong to the same period (Period 22). In a period, atomic radius decreases from left to right as the nuclear charge increases. LiLi (Atomic No. 33) is on the far left, and FF (Atomic No. 99) is on the far right.

Problem 3:

Compare the metallic character of Magnesium (Z=12Z=12) and Calcium (Z=20Z=20).

Solution:

Ca>MgCa > Mg

Explanation:

Both elements belong to Group 22. As we move down a group, the atomic size increases and the effective nuclear charge on the valence electrons decreases. This makes it easier for the atom to lose electrons. Therefore, Calcium is more metallic than Magnesium.