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Periodic Classification of Elements - Describe Dobereiner triads, Newlands law of octaves, and Mendeleev periodic table

Grade 10CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Dobereiner's Triads: In 1817, Johann Wolfgang Dobereiner identified groups of three elements with similar properties. He showed that when these elements were written in the order of increasing atomic masses, the atomic mass of the middle element was roughly the average of the atomic masses of the other two elements.

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Newlands' Law of Octaves: In 1866, John Newlands arranged elements in increasing order of atomic masses. He found that every eighth element had properties similar to those of the first, comparing this to the octaves found in music. This law was applicable only up to Calcium (CaCa).

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Mendeleev's Periodic Law: The properties of elements are a periodic function of their atomic masses. Mendeleev arranged the then-known 6363 elements based on their atomic masses and the similarity of their chemical properties (specifically the formulae of their hydrides and oxides).

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Mendeleev's Table Structure: The horizontal rows are called 'periods' and the vertical columns are called 'groups'. Mendeleev left gaps for elements like Scandium (ScSc), Gallium (GaGa), and Germanium (GeGe), naming them Eka-boron, Eka-aluminium, and Eka-silicon respectively.

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Limitations of Mendeleev's Classification: It could not assign a fixed position to Hydrogen (HH), isotopes of elements posed a challenge as they have different atomic masses but similar chemical properties, and in some cases, the order of atomic mass was subverted (e.g., Cobalt with mass 58.958.9 was placed before Nickel with mass 58.758.7).

📐Formulae

Arithmetic Mean (Dobereiner)=M1+M32\text{Arithmetic Mean (Dobereiner)} = \frac{M_1 + M_3}{2}

General Oxide Formula (Mendeleev’s Group I)=R2O\text{General Oxide Formula (Mendeleev's Group I)} = R_2O

General Hydride Formula (Mendeleev’s Group IV)=RH4\text{General Hydride Formula (Mendeleev's Group IV)} = RH_4

💡Examples

Problem 1:

Given the alkali metal triad: Lithium (LiLi) with atomic mass 6.96.9, Sodium (NaNa), and Potassium (KK) with atomic mass 39.139.1. Calculate the atomic mass of Sodium according to Dobereiner's Law of Triads.

Solution:

Atomic mass of Na=6.9+39.12=46.02=23.0\text{Atomic mass of } Na = \frac{6.9 + 39.1}{2} = \frac{46.0}{2} = 23.0

Explanation:

Dobereiner's Law states that the atomic mass of the middle element is approximately the arithmetic mean of the masses of the first and third elements. Here, 23.023.0 matches the actual atomic mass of Sodium.

Problem 2:

Identify the Mendeleevian prediction for Gallium (GaGa) and describe how it was validated.

Solution:

Mendeleev predicted an element named 'Eka-aluminium' with an atomic mass of about 6868. When Gallium was discovered later, its atomic mass was 69.769.7 and it formed an oxide Ga2O3Ga_2O_3 and a chloride GaCl3GaCl_3.

Explanation:

Mendeleev predicted properties based on the group trend. Eka-aluminium (EE) was expected to form E2O3E_2O_3, which matched Gallium's chemical behavior perfectly, proving the strength of his periodic table.