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Chemical Reactions and Equations - 1.31.3 1.31.3 HAHAHA

Grade 10CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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A chemical reaction is a process where the internal structure of substances changes to form new substances with different properties. It is represented by a chemical equation such as A+B→C+DA + B \rightarrow C + D.

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Balanced Chemical Equation: Based on the Law of Conservation of Mass, the total number of atoms of each element must remain the same before and after a chemical reaction. For example, 2H2+O2→2H2O2H_2 + O_2 \rightarrow 2H_2O.

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Combination Reaction: A reaction in which a single product is formed from two or more reactants. Example: CaO(s)+H2O(l)→Ca(OH)2(aq)+HeatCaO(s) + H_2O(l) \rightarrow Ca(OH)_2(aq) + \text{Heat}.

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Decomposition Reaction: A single reactant breaks down into two or more simpler products. This requires energy in the form of heat (Thermal), light (Photolytic), or electricity (Electrolytic).

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Displacement Reaction: A more reactive element displaces a less reactive element from its compound. Example: Fe(s)+CuSO4(aq)→FeSO4(aq)+Cu(s)Fe(s) + CuSO_4(aq) \rightarrow FeSO_4(aq) + Cu(s).

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Double Displacement Reaction: A reaction where there is an exchange of ions between the reactants to form new compounds, often resulting in a precipitate. Example: Na2SO4(aq)+BaCl2(aq)→BaSO4(s)↓+2NaCl(aq)Na_2SO_4(aq) + BaCl_2(aq) \rightarrow BaSO_4(s) \downarrow + 2NaCl(aq).

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Redox Reactions: Reactions involving both Oxidation (addition of oxygen or removal of hydrogen) and Reduction (removal of oxygen or addition of hydrogen).

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Exothermic and Endothermic Reactions: Exothermic reactions release energy to the surroundings (CH4+2O2→CO2+2H2O+EnergyCH_4 + 2O_2 \rightarrow CO_2 + 2H_2O + \text{Energy}), while endothermic reactions absorb energy (2AgCl→Sunlight2Ag+Cl22AgCl \xrightarrow{\text{Sunlight}} 2Ag + Cl_2).

📐Formulae

Mass of Reactants=Mass of Products\text{Mass of Reactants} = \text{Mass of Products}

6CO2(g)+12H2O(l)→Chlorophyll/SunlightC6H12O6(aq)+6O2(g)+6H2O(l)6CO_2(g) + 12H_2O(l) \xrightarrow{\text{Chlorophyll/Sunlight}} C_6H_{12}O_6(aq) + 6O_2(g) + 6H_2O(l)

C6H12O6(aq)+6O2(g)→6CO2(g)+6H2O(l)+EnergyC_6H_{12}O_6(aq) + 6O_2(g) \rightarrow 6CO_2(g) + 6H_2O(l) + \text{Energy}

2FeSO4(s)→ΔFe2O3(s)+SO2(g)+SO3(g)2FeSO_4(s) \xrightarrow{\Delta} Fe_2O_3(s) + SO_2(g) + SO_3(g)

💡Examples

Problem 1:

Balance the following chemical equation: Fe(s)+H2O(g)→Fe3O4(s)+H2(g)Fe(s) + H_2O(g) \rightarrow Fe_3O_4(s) + H_2(g)

Solution:

3Fe(s)+4H2O(g)→Fe3O4(s)+4H2(g)3Fe(s) + 4H_2O(g) \rightarrow Fe_3O_4(s) + 4H_2(g)

Explanation:

To balance the equation, we first balance the OO atoms by multiplying H2OH_2O by 44. This gives us 88 atoms of HH on the reactant side, so we multiply H2H_2 by 44 on the product side. Finally, we balance FeFe by multiplying it by 33 on the reactant side.

Problem 2:

Identify the substance oxidized and the substance reduced in the following reaction: CuO(s)+H2(g)→ΔCu(s)+H2O(g)CuO(s) + H_2(g) \xrightarrow{\Delta} Cu(s) + H_2O(g)

Solution:

Oxidized: H2H_2, Reduced: CuOCuO

Explanation:

In this reaction, H2H_2 gains oxygen to become H2OH_2O (Oxidation), and CuOCuO loses oxygen to become CuCu (Reduction).