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Chemical Reactions and Equations - Chemical equations

Grade 10CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

A chemical equation is the symbolic representation of a chemical reaction using the symbols and formulae of the substances involved. For example, the reaction between magnesium and oxygen is written as 2Mg+O2ightarrow2MgO2Mg + O_2 ightarrow 2MgO.

A balanced chemical equation is one in which the number of atoms of each element is the same on both the reactant and product sides. This is based on the Law of Conservation of Mass, which states that mass can neither be created nor destroyed in a chemical reaction.

A skeletal chemical equation is an unbalanced representation of a reaction where the mass is not necessarily the same on both sides, such as Mg+O2ightarrowMgOMg + O_2 ightarrow MgO.

To make a chemical equation more informative, physical states are mentioned: (s)(s) for solid, (l)(l) for liquid, (g)(g) for gas, and (aq)(aq) for aqueous (substance dissolved in water).

Specific conditions for a reaction, such as temperature, pressure, or a catalyst, are indicated above or below the arrow (ightarrow ightarrow) in the equation.

📐Formulae

ReactantsProductsReactants \rightarrow Products

Mass of Reactants=Mass of Products\text{Mass of Reactants} = \text{Mass of Products}

3Fe(s)+4H2O(g)Fe3O4(s)+4H2(g)3Fe(s) + 4H_2O(g) \rightarrow Fe_3O_4(s) + 4H_2(g)

CO(g)+2H2(g)340 atmCH3OH(l)CO(g) + 2H_2(g) \xrightarrow{340\text{ atm}} CH_3OH(l)

💡Examples

Problem 1:

Write and balance the chemical equation for the reaction between Hydrogen gas and Nitrogen gas to form Ammonia.

Solution:

3H2(g)+N2(g)2NH3(g)3H_2(g) + N_2(g) \rightarrow 2NH_3(g)

Explanation:

Initially, the skeletal equation is H2+N2NH3H_2 + N_2 \rightarrow NH_3. To balance the Nitrogen atoms, we add a coefficient of 22 to NH3NH_3. This gives 22 Nitrogen atoms on both sides but 66 Hydrogen atoms on the product side. To balance Hydrogen, we add a coefficient of 33 to H2H_2 on the reactant side.

Problem 2:

Balance the following chemical equation: NaOH+H2SO4Na2SO4+H2ONaOH + H_2SO_4 \rightarrow Na_2SO_4 + H_2O.

Solution:

2NaOH+H2SO4Na2SO4+2H2O2NaOH + H_2SO_4 \rightarrow Na_2SO_4 + 2H_2O

Explanation:

Count the atoms of each element. There are 22 Sodium (NaNa) atoms on the product side, so we add 22 before NaOHNaOH. This results in 44 Hydrogen atoms and 66 Oxygen atoms on the reactant side. To balance these, we add a coefficient of 22 before H2OH_2O on the product side.

Chemical equations - Revision Notes & Key Formulas | CBSE Class 10 Science