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Nuclei - Radioactivity

Grade 12CBSEPhysics

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Radioactivity is a spontaneous process by which an unstable nucleus emits radiations like α\alpha, β\beta, or γ\gamma rays to achieve stability.

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The Law of Radioactive Decay states that the number of nuclei disintegrating per unit time is directly proportional to the total number of nuclei present at that instant: dNdt=−λN\frac{dN}{dt} = -\lambda N.

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Decay Constant (λ\lambda) is the probability of decay of a nucleus per unit time. It is characteristic of the radioactive substance and independent of physical conditions.

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Half-life (T1/2T_{1/2}) is the time interval during which the number of radioactive nuclei reduces to half of its initial value.

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Mean life (τ\tau) is the average lifetime of all the nuclei in a radioactive sample, given by τ=1λ\tau = \frac{1}{\lambda}.

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Activity (RR) of a sample is the rate of disintegration. Its SI unit is the Becquerel (1 Bq=1 disintegration per second1 \text{ Bq} = 1 \text{ disintegration per second}). Another common unit is the Curie (1 Ci=3.7×1010 Bq1 \text{ Ci} = 3.7 \times 10^{10} \text{ Bq}).

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α\alpha-decay: The nucleus loses 2 protons and 2 neutrons, represented as ZAX→Z−2A−4Y+24He_Z^A X \rightarrow _{Z-2}^{A-4} Y + _2^4 He.

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β−\beta^--decay: A neutron converts into a proton, emitting an electron and an antineutrino: ZAX→Z+1AY+e−+νˉ_Z^A X \rightarrow _{Z+1}^{A} Y + e^- + \bar{\nu}.

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γ\gamma-decay: The nucleus transitions from an excited state to a lower energy state by emitting a high-energy photon, with no change in AA or ZZ.

📐Formulae

N(t)=N0e−λtN(t) = N_0 e^{-\lambda t}

R=∣dNdt∣=λNR = \left| \frac{dN}{dt} \right| = \lambda N

T1/2=ln⁡2λ≈0.693λT_{1/2} = \frac{\ln 2}{\lambda} \approx \frac{0.693}{\lambda}

τ=1λ=T1/20.693≈1.44T1/2\tau = \frac{1}{\lambda} = \frac{T_{1/2}}{0.693} \approx 1.44 T_{1/2}

N=N0(12)n where n=tT1/2N = N_0 \left( \frac{1}{2} \right)^n \text{ where } n = \frac{t}{T_{1/2}}

R=R0e−λtR = R_0 e^{-\lambda t}

💡Examples

Problem 1:

A radioactive sample has a half-life of 1010 days. If the initial number of nuclei is 80,000,00080,000,000, find the number of nuclei remaining after 3030 days and determine how many nuclei disintegrated.

Solution:

  1. Calculate the number of half-lives: n=tT1/2=3010=3n = \frac{t}{T_{1/2}} = \frac{30}{10} = 3.
  2. Find the remaining nuclei: N=N0(12)3=80,000,000×18=10,000,000N = N_0 \left( \frac{1}{2} \right)^3 = 80,000,000 \times \frac{1}{8} = 10,000,000.
  3. Calculate disintegrated nuclei: Ndecayed=N0−NN_{decayed} = N_0 - N. 80000000−1000000070000000\begin{array}{r} 80000000 \\ -10000000 \\ \hline 70000000 \end{array}

Explanation:

The number of nuclei reduces by half every 1010 days. After 33 half-lives, the sample is reduced to 18\frac{1}{8} of its original count. The number of disintegrated nuclei is the simple difference between the initial and final counts.

Problem 2:

The decay constant of a radioactive substance is 0.05 year−10.05 \text{ year}^{-1}. Calculate the mean life of the substance.

Solution:

Using the relation between mean life and decay constant: τ=1λ\tau = \frac{1}{\lambda} τ=10.05=20 years\tau = \frac{1}{0.05} = 20 \text{ years}

Explanation:

The mean life τ\tau is the reciprocal of the decay constant λ\lambda. For a substance with λ=0.05\lambda = 0.05, the average time a nucleus survives is 2020 years.