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Statistics and Probability - Data presentation

Grade 11IB_AI

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Data can be classified as Qualitative (categorical) or Quantitative (numerical). Quantitative data is further divided into Discrete (countable values) and Continuous (measurable values, e.g., h∈Rh \in \mathbb{R}).

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Grouped Frequency Tables are used for large datasets. For calculations like the mean, the mid-interval value xx is used: x=lower limit+upper limit2x = \frac{\text{lower limit} + \text{upper limit}}{2}.

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Cumulative Frequency is the running total of frequencies. A cumulative frequency graph (ogive) is used to estimate the median (50th50^{th} percentile) and quartiles (25th25^{th} and 75th75^{th} percentiles).

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Box-and-whisker plots represent the five-number summary: minimum value, lower quartile (Q1Q_1), median (Q2Q_2), upper quartile (Q3Q_3), and maximum value.

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Outliers are extreme values that are numerically distant from the rest of the data. The standard IB AI criteria involves the Interquartile Range (IQRIQR).

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Histograms are used for continuous data. The area of the bar represents the frequency. In most IB AI SL contexts, class widths are equal, so the height of the bar represents the frequency.

📐Formulae

xˉ=∑fixin\bar{x} = \frac{\sum f_i x_i}{n}

IQR=Q3−Q1IQR = Q_3 - Q_1

Lower Outlier Boundary=Q1−1.5×IQR\text{Lower Outlier Boundary} = Q_1 - 1.5 \times IQR

Upper Outlier Boundary=Q3+1.5×IQR\text{Upper Outlier Boundary} = Q_3 + 1.5 \times IQR

σ=∑fi(xi−xˉ)2n\sigma = \sqrt{\frac{\sum f_i (x_i - \bar{x})^2}{n}}

💡Examples

Problem 1:

Given a set of data with Q1=15Q_1 = 15 and Q3=25Q_3 = 25, determine if a value of 4242 is considered an outlier.

Solution:

IQR=25−15=10IQR = 25 - 15 = 10 Upper Boundary=Q3+1.5×IQR\text{Upper Boundary} = Q_3 + 1.5 \times IQR Upper Boundary=25+1.5(10)=25+15=40\text{Upper Boundary} = 25 + 1.5(10) = 25 + 15 = 40 Since 42>4042 > 40, the value 4242 is an outlier.

Explanation:

To identify outliers, calculate the Interquartile Range first, then find the upper boundary. Any value exceeding this boundary is an outlier.

Problem 2:

The following table shows the frequency of scores in a small quiz:

Score (x)Frequency (f)52105153\begin{array}{|c|c|} \hline \text{Score } (x) & \text{Frequency } (f) \\ \hline 5 & 2 \\ 10 & 5 \\ 15 & 3 \\ \hline \end{array} Calculate the mean score xˉ\bar{x}.

Solution:

∑fixi=(5×2)+(10×5)+(15×3)=10+50+45=105\sum f_i x_i = (5 \times 2) + (10 \times 5) + (15 \times 3) = 10 + 50 + 45 = 105 n=∑fi=2+5+3=10n = \sum f_i = 2 + 5 + 3 = 10 xˉ=10510=10.5\bar{x} = \frac{105}{10} = 10.5

Explanation:

The mean is calculated by summing the product of each score and its frequency, then dividing by the total number of observations (nn).