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Number - Direct and inverse proportion

Grade 10IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Direct Proportion: Two variables xx and yy are in direct proportion if one is a constant multiple of the other. As xx increases, yy increases at a constant rate. This is written as y∝xy \propto x.

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The constant of proportionality, kk, is a non-zero constant such that y=kxy = kx. The graph of direct proportion is a straight line passing through the origin (0,0)(0,0).

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Inverse Proportion: Two variables xx and yy are in inverse proportion if one variable increases as the other decreases such that their product remains constant. This is written as y∝1xy \propto \frac{1}{x}.

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For inverse proportion, the relationship is defined by the equation y=kxy = \frac{k}{x} or xy=kxy = k. The graph is a hyperbola that never touches the axes.

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Proportionality to powers: Variables can also be proportional to squares or cubes, such as y∝x2y \propto x^2 (direct square) or y∝1x2y \propto \frac{1}{x^2} (inverse square).

📐Formulae

y=kxy = kx

y=kxy = \frac{k}{x}

y=kx2y = kx^2

y=kxy = \frac{k}{\sqrt{x}}

💡Examples

Problem 1:

Given that yy is directly proportional to xx, and y=20y = 20 when x=4x = 4, find the value of yy when x=9x = 9.

Solution:

y=kxy = kx Substituting the known values: 20=k×420 = k \times 4 k=204=5k = \frac{20}{4} = 5 Now find yy for x=9x = 9: y=5×9y = 5 \times 9 y=45y = 45

Explanation:

First, establish the general equation for direct proportion. Use the given values to solve for the constant kk. Then, use kk to solve for the unknown variable.

Problem 2:

The variable zz is inversely proportional to ww. If z=10z = 10 when w=2w = 2, find zz when w=5w = 5.

Solution:

z=kwz = \frac{k}{w} Substituting the known values: 10=k210 = \frac{k}{2} k=10×2=20k = 10 \times 2 = 20 Now find zz for w=5w = 5: z=205z = \frac{20}{5} z=4z = 4

Explanation:

Identify the inverse relationship and set up the equation z=kwz = \frac{k}{w}. Calculate kk by multiplying the given zz and ww values, then divide kk by the new ww to find the result.

Problem 3:

A quantity AA is directly proportional to the square of rr. When r=3r = 3, A=18A = 18. Find AA when r=5r = 5.

Solution:

A=kr2A = kr^2 Substituting the known values: 18=k×3218 = k \times 3^2 18=9k18 = 9k k=2k = 2 Now find AA for r=5r = 5: A=2×52A = 2 \times 5^2 A=2×25A = 2 \times 25 A=50A = 50

Explanation:

Since AA is proportional to the square of rr, the equation is A=kr2A = kr^2. Square the value of rr before solving for kk or AA.