d and f Block Elements
Each subtopic includes About section, revision page link, 10 preview questions, and practice CTAs.
General introduction and electronic configuration
SubtopicGeneral introduction and electronic configuration under d and f Block Elements for Grade 12 ICSE.
Preview questions (no answers)
- 1.
The transition series that includes the element Platinum () is the:
A.series
B.series
C.series
D.series
- 2.
The valence shell electronic configuration of Group 3 elements like Scandium is generally represented as:
A.B.C.D. - 3.
Which of the following elements is a liquid at room temperature and belongs to the -block?
A.Bromine
B.Gallium
C.Mercury
D.Cesium
- 4.
What is the number of -electrons in ()?
A.6
B.5
C.4
D.3
- 5.
Ruthenium () is an element in the transition series that exhibits an anomalous ground state electronic configuration due to the relative energies of its orbitals. Based on the classification of transition series elements shown in the diagram, which of the following represents the correct ground state electronic configuration of Ruthenium?
A.B.C.D. - 6.
Which of the following -block elements has the maximum number of stable oxidation states?
A.Scandium
B.Manganese
C.Zinc
D.Titanium
- 7.
Electronic configuration of () is:
A.B.C.D. - 8.
Why is the density of series elements much higher than that of series elements?
A.Because the atomic volume remains almost the same while mass increases significantly.
B.Because elements have more electrons.
C.Because of the decrease in nuclear charge.
D.Because elements are more metallic.
- 9.
Which of the following ions is expected to have a magnetic moment of ?
A.B.C.D. - 10.
The electronic configuration corresponds to which lanthanoid?
A.Lanthanum
B.Cerium
C.Praseodymium
D.Neodymium
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Characteristics of transition metals
SubtopicCharacteristics of transition metals under d and f Block Elements for Grade 12 ICSE.
Preview questions (no answers)
- 1.
Transition metals like Iron (, ) exhibit variable oxidation states by losing electrons from their outer and inner subshells. Based on the electron loss sequence provided in the flowchart, which of the following pairs represents the most common oxidation states of Iron?
A.and
B.and
C.and
D.and
- 2.
Which of the following alloys contains a transition metal and a non-metal?
A.Brass
B.Bronze
C.Steel
D.Solder
- 3.
Lanthanoid contraction is caused by:
A.Perfect shielding of 4f electrons
B.Poor shielding effect of 4f electrons
C.Increase in atomic size
D.Decrease in effective nuclear charge
- 4.
Which of the following is a paramagnetic ion?
A.B.C.D. - 5.
Although Fluorine is more electronegative than Oxygen, the highest oxidation state of Manganese is observed in its oxide () where it is , whereas in its fluoride (), it is only . Based on the bonding characteristics represented in the diagram, what is the primary reason for this difference?
A.Fluorine is a stronger oxidizing agent than Oxygen.
B.Oxygen has the ability to form multiple bonds with the metal via overlapping.
C.The lattice energy of Manganese Fluoride is higher than that of Manganese Oxide.
D.Fluorine atoms are larger than Oxygen atoms, causing steric hindrance.
- 6.
The color of transition metal ions is attributed to the excitation of an electron from a lower energy -orbital to a higher energy -orbital. Based on the Crystal Field splitting diagram shown below for an octahedral field, which of the following ions is colorless because it possesses a electronic configuration?
A.B.C.D. - 7.
Which lanthanoid element is obtained by synthetic means (not found in nature)?
A.Promethium (Pm)
B.Gadolinium (Gd)
C.Lutetium (Lu)
D.Cerium (Ce)
- 8.
The deviation of () and () from the theoretical magnetic moment calculated by the LandΓ© formula at is a significant anomaly in lanthanoid chemistry. This deviation occurs because:
A.The electrons are so well-shielded that the spin-orbit coupling constant becomes negligible.
B.The energy gap between the ground state level and the first excited state is small enough to allow thermal population.
C.The ions experience a transition from high-spin to low-spin configuration due to strong crystal field effects.
D.These specific ions undergo spontaneous disproportionation in aqueous solution, changing the count of unpaired electrons.
- 9.
Potassium hexachloroplatinate () is a stable compound, whereas the corresponding nickel compound is not known to exist under ordinary conditions. This marked difference in the stability of the oxidation state between Nickel and Platinum is primarily attributed to which thermodynamic factor?
A.The higher lattice energy associated with Platinum complexes due to its larger ionic radius.
B.The orbitals of Platinum being more effectively shielded by electrons than orbitals of Nickel.
C.The higher electronegativity of Platinum which prevents the loss of four electrons.
D.The sum of the first four ionization enthalpies being significantly lower for than for .
- 10.
The acidic character of the oxides of a particular transition metal follows which trend?
A.Increases with an increase in the oxidation state of the metal.
B.Decreases with an increase in the oxidation state of the metal.
C.Remains constant regardless of the oxidation state.
D.First increases then decreases as the oxidation state increases.
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Variation in atomic and ionic radii
SubtopicVariation in atomic and ionic radii under d and f Block Elements for Grade 12 ICSE.
Preview questions (no answers)
- 1.
Which of the following ions has the smallest radius in the first transition series?
A.B.C.D. - 2.
Which of the following elements has an atomic radius very similar to Rhenium ()?
A.Manganese ()
B.Technetium ()
C.Cobalt ()
D.Iridium ()
- 3.
What is the trend in atomic radius from to to ?
A.Decrease
B.Increase
C.First increase then decrease
D.First decrease then increase
- 4.
Which element in the series has an atomic radius most similar to that of ?
A.B.C.D. - 5.
Which of the following factors contributes to the Actinoid contraction more than to the Lanthanoid contraction?
A.The shape of the orbitals is more diffused than .
B.The electrons are more effective at shielding.
C.The nuclear charge is lower in actinoids.
D.The electrons are closer to the nucleus than .
- 6.
What happens to the atomic radii of -block elements when moving down from the second () to the third () transition series?
A.It increases significantly.
B.It decreases significantly.
C.It remains almost the same due to Lanthanoid contraction.
D.It doubles.
- 7.
In the series, the decrease in atomic radius is most significant between:
A.and
B.and
C.and
D.and
- 8.
Which of the following is a result of the d-block contraction occurring after the series is filled?
A.The radius of being smaller than .
B.The radius of being the same as .
C.The radius of being larger than .
D.The radius of being larger than .
- 9.
Considering the Lanthanoid series, which of the following properties shows a decrease as the ionic radius decreases?
A.Electronegativity
B.Hydration energy of ions
C.Ionic character of the bond
D.Stability of complexes
- 10.
In the series, has a radius of and has . This decrease is due to:
A.The addition of an electron to the set in an octahedral field.
B.Increased nuclear charge with poor shielding by the electron.
C.The contraction of the shell.
D.The change from a to a state.
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Oxidation states and Ionization enthalpy
SubtopicOxidation states and Ionization enthalpy under d and f Block Elements for Grade 12 ICSE.
Preview questions (no answers)
- 1.
Which oxidation state of Manganese is the most stable in acidic aqueous solution?
A.+7
B.+4
C.+2
D.+3
- 2.
Among the series, which element's is unexpectedly low because it leads to a configuration?
A.Copper
B.Zinc
C.Chromium
D.Manganese
- 3.
What is the common oxidation state of Silver () in its compounds?
A.+1
B.+2
C.+3
D.0
- 4.
The element () shows only oxidation state because:
A.It has an empty orbital
B.It has a half-filled orbital
C.It has a completely filled orbital ()
D.It is a transition metal
- 5.
Which of the following transition metal ions has the highest ?
A.B.C.D. - 6.
The ionic radius of ions decreases across the series. How does this affect the ionization enthalpy?
A.Ionization enthalpy decreases as the radius decreases
B.Ionization enthalpy increases as the radius decreases
C.Ionization enthalpy remains constant
D.Ionization enthalpy becomes zero
- 7.
Why is the oxidation state of Chromium in a strong oxidizing agent, while the state of Tungsten in is stable?
A.In heavier transition metals, higher oxidation states are more stable
B.In lighter transition metals, higher oxidation states are more stable
C.Tungsten has a lower than Chromium
D.Chromium has a larger atomic radius
- 8.
What is the primary reason that is a strong reducing agent while is a strong oxidizing agent?
A.Both tend to revert to the most stable oxidation state common to lanthanoids
B.Europium is more metallic than Cerium
C.The configuration of is less stable than the configuration of
D.Ionization enthalpy for Cerium is much lower than for Europium
- 9.
Which of the following ions is paramagnetic and has the highest stable oxidation state in its respective series?
A.B.C.D.None of these
- 10.
The ionization enthalpy of the 5d elements is higher than 4d. This trend is a deviation from the usual group trend. Which other property shows a similar anomalous trend due to the same reason?
A.Atomic Radii (they are nearly identical for 4d and 5d)
B.Electronegativity (it decreases significantly)
C.Melting Point (it decreases significantly)
D.Hydration Enthalpy (it becomes positive)
Download the worksheet for d and f Block Elements - Oxidation states and Ionization enthalpy to practice offline. It includes additional chapter-level practice questions.
Catalytic properties and Magnetic properties
SubtopicCatalytic properties and Magnetic properties under d and f Block Elements for Grade 12 ICSE.
Preview questions (no answers)
- 1.
What is the magnetic moment of ion ()?
A.B.C.D. - 2.
In the lead chamber process, which of the following acts as a catalyst?
A.Oxides of nitrogen
B.Platinum powder
C.Vanadium oxide
D.Nickel
- 3.
Which of the following is paramagnetic?
A.B.C.D. - 4.
Magnetic moment of is same as that of:
A.B.C.D. - 5.
What is the magnetic moment of ()?
A.BM
B.BM
C.BM
D.BM
- 6.
Identify the incorrect statement regarding transition metal catalysts.
A.They provide a large surface area for reactants.
B.They can form unstable intermediate complexes.
C.They always remain in the same oxidation state throughout the mechanism.
D.They lower the activation energy of the reaction.
- 7.
A transition metal ion has a magnetic moment of BM. If its atomic number is , what is the value of ?
A.1
B.2
C.3
D.4
- 8.
In the transition series, the magnetic moment of ions typically corresponds to the 'spin-only' value because the orbital angular momentum is 'quenched' by the surrounding ligand field. In contrast, for the lanthanide series (), the magnetic moment is determined by the total angular momentum quantum number because the orbital contribution is preserved. Which of the following provides the correct structural explanation for why the orbital angular momentum is NOT quenched in lanthanides?
A.The crystal field splitting energy () in lanthanide complexes is significantly larger than the spin-orbit coupling constant (), forcing the electrons into a fixed orbital state.
B.The electrons are located further from the nucleus than the and electrons, which minimizes their overlap with the ligand field.
C.The orbitals are spatially shielded from the external ligand environment by the overlying filled and subshells.
D.The subshell always remains in a high-spin state regardless of the ligand field strength, which prevents any loss of orbital angular momentum.
- 9.
Why is a better catalyst than in many oxidation-reduction reactions involving peroxide?
A.Because has a higher charge density to polarize the bond.
B.Because is more stable and cannot be reduced.
C.Because is diamagnetic and does not interfere with the spin of oxygen.
D.Because has a configuration.
- 10.
Calculate the magnetic moment of () using the spin-only formula and identify the discrepancy with its actual magnetic moment ( BM).
A.Calculated = 2.83 BM; Actual is higher due to orbital contribution.
B.Calculated = 1.73 BM; Actual is higher due to unpaired electrons.
C.Calculated = 3.87 BM; Actual is lower due to pairing.
D.Calculated = 0 BM; Actual is higher due to nuclear spin.
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Preparation and properties of K2Cr2O7 and KMnO4
SubtopicPreparation and properties of K2Cr2O7 and KMnO4 under d and f Block Elements for Grade 12 ICSE.
Preview questions (no answers)
- 1.
Which compound is formed when is dissolved in solution?
A.B.C.D. - 2.
What is the equivalent mass of when it is reduced to in a strongly basic medium?
A.Molecular mass / 1
B.Molecular mass / 3
C.Molecular mass / 5
D.Molecular mass / 2
- 3.
Which of the following is used to remove the yellow color of iron(III) during the preparation of from chromite?
A.Filtering out insoluble
B.Adding more acid
C.Adding
D.Heating the solution
- 4.
In the alkaline oxidation of thiosulfate () by , the sulfur is oxidized to:
A.B.C.D. - 5.
What is the change in the oxidation state of Manganese when reacts with in an acidic medium?
A.+7 to +4
B.+7 to +2
C.+7 to +6
D.+6 to +4
- 6.
Which of the following properties is shared by both and ?
A.Both are green in color
B.Both have tetrahedral geometry
C.Both are paramagnetic
D.Both are used as primary standards
- 7.
What is the equivalent weight of () in a strongly alkaline reaction where it is reduced to ?
A.M/5
B.M/3
C.M/1
D.M/6
- 8.
How many oxygen atoms are shared between the two tetrahedra in ?
A.0
B.1
C.2
D.3
- 9.
In the reaction , the n-factor of is:
A.1
B.2
C.5
D.10
- 10.
Which statement is true about the structure of ?
A.It is isostructural with .
B.The atom is in octahedral geometry.
C.It has one unpaired electron.
D.The bond angles are exactly .
Download the worksheet for d and f Block Elements - Preparation and properties of K2Cr2O7 and KMnO4 to practice offline. It includes additional chapter-level practice questions.
Lanthanoids and Actinoids
SubtopicLanthanoids and Actinoids under d and f Block Elements for Grade 12 ICSE.
Preview questions (no answers)
- 1.
The solubility of lanthanoid hydroxides in water is generally:
A.High
B.Low
C.Infinite
D.Same as alkali hydroxides
- 2.
Which of the following lanthanoids has the smallest ionic radius in the +3 state?
A.B.C.D. - 3.
Actinoids are called inner transition elements because they involve the filling of:
A.Outer s-orbital
B.Penultimate d-orbital
C.Anti-penultimate f-orbital
D.Outer p-orbital
- 4.
Which of the following is an example of a lanthanoid metal used in magnesium-based alloys for jet engines?
A.Cerium
B.Neodymium
C.Iron
D.Sodium
- 5.
The term 'inner-transition elements' is applied to -block elements because:
A.They are found in the interior of the Earth
B.The last electron enters the orbital
C.They have very high densities
D.They are mostly radioactive
- 6.
Lanthanoid hydroxides react with to form:
A.Carbonates ()
B.Bicarbonates ()
C.Oxides ()
D.No reaction
- 7.
Which element in the actinoid series has the electronic configuration ?
A.Actinium ()
B.Thorium ()
C.Protactinium ()
D.Uranium ()
- 8.
Which of the following statements about the densities of lanthanoids is true?
A.Densities generally increase from to with anomalies at and .
B.Densities decrease from to due to the increase in atomic volume.
C.All lanthanoids have approximately the same density of .
D.Densities increase linearly without any exceptions across the series.
- 9.
The chemical behavior of 'early' actinoids (up to ) is more similar to transition metals than 'late' actinoids. This is because:
A.The electrons in early actinoids are less shielded and participate in bonding.
B.Early actinoids have fewer protons.
C.Early actinoids have larger atomic radii.
D.Late actinoids have completely filled orbitals.
- 10.
Which actinoid is used as a fuel in nuclear reactors in the form of its oxide mixed with (MOX fuel)?
A.Plutonium ()
B.Thorium ()
C.Americium ()
D.Neptunium ()
Download the worksheet for d and f Block Elements - Lanthanoids and Actinoids to practice offline. It includes additional chapter-level practice questions.
Lanthanoid contraction
SubtopicLanthanoid contraction under d and f Block Elements for Grade 12 ICSE.
Preview questions (no answers)
- 1.
Which element is the first member of the lanthanide series?
A.Lanthanum ()
B.Cerium ()
C.Actinium ()
D.Thorium ()
- 2.
The melting points of lanthanides generally increase across the series. This is primarily because of:
A.Decreased nuclear charge
B.Increased atomic size
C.Increased interatomic forces due to contraction
D.Decreased density
- 3.
Which oxidation state is shown by Europium () due to the stability of a half-filled subshell?
A.B.C.D. - 4.
The ionic radius of is very close to which of the following lanthanoid ions?
A.B.C.D. - 5.
The Lanthanoid contraction is fundamentally caused by the 'poor shielding' of the nuclear charge by electrons. Hypothetically, if the shielding provided by each electron were 'perfect' (where the increase in the shielding constant exactly matches the increase in atomic number), how would the atomic radii of the Lanthanoids most likely behave as the atomic number increases from to ?
A.The atomic radii would decrease at a significantly higher rate than currently observed.
B.The atomic radii would remain relatively constant as the effective nuclear charge would not change.
C.The atomic radii would increase drastically because the subshell is becoming more crowded.
D.The atomic radii would fluctuate based on whether the electrons are paired or unpaired.
- 6.
What effect does Lanthanoid contraction have on the standard electrode potential of compared to ?
A.No effect
B.Makes much more reactive than
C.Makes less reactive (more noble) than expected
D.Makes a gas
- 7.
In the series of Lanthanoid tripositive ions (), which ion has the highest polarizing power?
A.B.C.D. - 8.
The melting points of the lanthanoid metals generally increase from to (with exceptions for and ). This trend is primarily due to:
A.Increasing atomic mass
B.Increasing strength of metallic bonding as the atomic size decreases
C.Increasing number of unpaired electrons
D.Transition from to structure
- 9.
The 'Shielding Constant' () for electrons in lanthanoids increases as the atomic number increases. Why doesn't this negate the contraction?
A.The nuclear charge () increases by unit, but increases by only about units per electron
B.The shielding constant actually decreases across the series
C.The electrons provide a negative shielding
D.The electrons are outside the and shells
- 10.
In the series , the ionic radius and atomic number are related such that:
A.B.C.There is a steady decrease in with increasing
D.There is a steady increase in with increasing
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