Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
The -block elements are called inner transition elements because they involve the filling of the subshell. They consist of two series: Lanthanoids ( series) and Actinoids ( series).
General electronic configuration of Lanthanoids is and for Actinoids it is .
Lanthanoid Contraction: The steady decrease in the atomic and ionic radii (specifically ions) with increase in atomic number. This is caused by the poor shielding effect of electrons against the increasing nuclear charge.
Consequences of Lanthanoid Contraction: It leads to the similarity in the chemical properties of elements of the second () and third () transition series, such as and having nearly identical radii.
Oxidation States: The most common oxidation state for both series is . However, Lanthanoids exhibit and if they lead to stable , or configurations (e.g., is and is ).
Actinoids show a wider range of oxidation states (up to ) compared to Lanthanoids because the energy difference between , and subshells is very small, allowing more electrons to participate in bond formation.
Actinoid Contraction: Similar to Lanthanoid contraction, but more pronounced due to even poorer shielding by electrons compared to electrons.
Chemical Reactivity: Lanthanoids are highly electropositive and resemble Calcium in reactivity. Actinoids are even more reactive, especially when finely divided, and many are radioactive (transuranic elements).
📐Formulae
💡Examples
Problem 1:
Explain why is a strong oxidizing agent even though it has a stable configuration.
Solution:
() tends to revert to the most stable oxidation state of the Lanthanoid series, which is ().
Explanation:
Since gains an electron to become , it acts as a strong oxidizing agent. The value for is .
Problem 2:
Compare the basicity of and .
Solution:
is more basic than .
Explanation:
Due to Lanthanoid contraction, the size of ions decreases from to . According to Fajan's rules, a decrease in size increases the covalent character of the bond. Therefore, is more covalent and less basic than .
Problem 3:
Calculate the magnetic moment of ().
Solution:
Explanation:
The electronic configuration of is . For , the configuration is , meaning there are unpaired electrons. Using , we get .