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d and f Block Elements - Preparation and properties of K2Cr2O7 and KMnO4

Grade 12ICSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Potassium Dichromate (K2Cr2O7K_2Cr_2O_7) is prepared from chromite ore (FeCr2O4FeCr_2O_4) via three steps: (i) roasting with Na2CO3Na_2CO_3 to form yellow Na2CrO4Na_2CrO_4, (ii) acidification with H2SO4H_2SO_4 to form orange Na2Cr2O7Na_2Cr_2O_7, and (iii) treatment with KClKCl to crystallize K2Cr2O7K_2Cr_2O_7.

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In aqueous solution, chromate (CrO42βˆ’CrO_4^{2-}) and dichromate (Cr2O72βˆ’Cr_2O_7^{2-}) ions exist in equilibrium. Chromate is stable at pH>7pH > 7 (yellow), while dichromate is stable at pH<7pH < 7 (orange).

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Potassium Permanganate (KMnO4KMnO_4) is prepared from pyrolusite ore (MnO2MnO_2) by fusion with alkali (KOHKOH) and an oxidizing agent (O2O_2 or KNO3KNO_3) to form green K2MnO4K_2MnO_4, followed by electrolytic oxidation or disproportionation in acidic medium.

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KMnO4KMnO_4 acts as a powerful oxidizing agent in acidic, neutral, and alkaline media. In acidic medium (H2SO4H_2SO_4), it is reduced to Mn2+Mn^{2+}, involving a change of 5 electrons.

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K2Cr2O7K_2Cr_2O_7 is used as a primary standard in volumetric analysis, whereas KMnO4KMnO_4 is not because it can be easily reduced by impurities and is affected by light.

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The structures: CrO42βˆ’CrO_4^{2-} is tetrahedral, while Cr2O72βˆ’Cr_2O_7^{2-} consists of two tetrahedra sharing one oxygen atom with a Crβˆ’Oβˆ’CrCr-O-Cr bond angle of 126∘126^\circ.

πŸ“Formulae

4FeCr2O4+8Na2CO3+7O2β†’8Na2CrO4+2Fe2O3+8CO24FeCr_2O_4 + 8Na_2CO_3 + 7O_2 \rightarrow 8Na_2CrO_4 + 2Fe_2O_3 + 8CO_2

2Na2CrO4+2H+β†’Na2Cr2O7+2Na++H2O2Na_2CrO_4 + 2H^+ \rightarrow Na_2Cr_2O_7 + 2Na^+ + H_2O

Cr2O72βˆ’+14H++6eβˆ’β†’2Cr3++7H2O(E∘=+1.33V)Cr_2O_7^{2-} + 14H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O \quad (E^\circ = +1.33 V)

2MnO2+4KOH+O2β†’2K2MnO4+2H2O2MnO_2 + 4KOH + O_2 \rightarrow 2K_2MnO_4 + 2H_2O

MnO4βˆ’+8H++5eβˆ’β†’Mn2++4H2O(E∘=+1.51V)MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O \quad (E^\circ = +1.51 V)

2MnO4βˆ’+H2O+Iβˆ’β†’2MnO2+2OHβˆ’+IO3βˆ’Β (InΒ neutral/alkalineΒ medium)2MnO_4^- + H_2O + I^- \rightarrow 2MnO_2 + 2OH^- + IO_3^- \text{ (In neutral/alkaline medium)}

πŸ’‘Examples

Problem 1:

Write the balanced ionic equation for the reaction between acidified K2Cr2O7K_2Cr_2O_7 and Fe2+Fe^{2+} ions.

Solution:

Cr2O72βˆ’+14H++6Fe2+β†’2Cr3++6Fe3++7H2OCr_2O_7^{2-} + 14H^+ + 6Fe^{2+} \rightarrow 2Cr^{3+} + 6Fe^{3+} + 7H_2O

Explanation:

In an acidic medium, dichromate ion acts as an oxidizing agent and is reduced to Cr3+Cr^{3+}. It oxidizes ferrous ions (Fe2+Fe^{2+}) to ferric ions (Fe3+Fe^{3+}). The n-factor for Cr2O72βˆ’Cr_2O_7^{2-} is 6.

Problem 2:

What happens when KMnO4KMnO_4 reacts with H2C2O4H_2C_2O_4 (Oxalic acid) in the presence of H2SO4H_2SO_4 at 333K333K?

Solution:

2MnO4βˆ’+16H++5C2O42βˆ’β†’2Mn2++10CO2+8H2O2MnO_4^- + 16H^+ + 5C_2O_4^{2-} \rightarrow 2Mn^{2+} + 10CO_2 + 8H_2O

Explanation:

Acidified permanganate oxidizes oxalic acid to carbon dioxide gas. The reaction is slow initially but becomes fast due to the autocatalytic effect of Mn2+Mn^{2+} ions formed during the process.

Problem 3:

Explain the effect of increasing pHpH on a solution of K2Cr2O7K_2Cr_2O_7.

Solution:

Cr2O72βˆ’+2OHβˆ’β†’2CrO42βˆ’+H2OCr_2O_7^{2-} + 2OH^- \rightarrow 2CrO_4^{2-} + H_2O

Explanation:

Increasing the pHpH means adding a base. The OHβˆ’OH^- ions react with the dichromate ions (orange) to convert them into chromate ions (yellow). Thus, the color changes from orange to yellow.

Preparation and properties of K2Cr2O7 and KMnO4 Revision - Class 12 Chemistry ICSE