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d and f Block Elements - Preparation and properties of K2Cr2O7 and KMnO4

Grade 12ICSEChemistry

Review the key concepts, formulae, and examples before starting your quiz.

πŸ”‘Concepts

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Potassium Dichromate (K2Cr2O7K_2Cr_2O_7) is prepared from chromite ore (FeCr2O4FeCr_2O_4) via three steps: (i) roasting with Na2CO3Na_2CO_3 to form yellow Na2CrO4Na_2CrO_4, (ii) acidification with H2SO4H_2SO_4 to form orange Na2Cr2O7Na_2Cr_2O_7, and (iii) treatment with KClKCl to crystallize K2Cr2O7K_2Cr_2O_7.

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In aqueous solution, chromate (CrO42βˆ’CrO_4^{2-}) and dichromate (Cr2O72βˆ’Cr_2O_7^{2-}) ions exist in equilibrium. Chromate is stable at pH>7pH > 7 (yellow), while dichromate is stable at pH<7pH < 7 (orange).

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Potassium Permanganate (KMnO4KMnO_4) is prepared from pyrolusite ore (MnO2MnO_2) by fusion with alkali (KOHKOH) and an oxidizing agent (O2O_2 or KNO3KNO_3) to form green K2MnO4K_2MnO_4, followed by electrolytic oxidation or disproportionation in acidic medium.

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KMnO4KMnO_4 acts as a powerful oxidizing agent in acidic, neutral, and alkaline media. In acidic medium (H2SO4H_2SO_4), it is reduced to Mn2+Mn^{2+}, involving a change of 5 electrons.

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K2Cr2O7K_2Cr_2O_7 is used as a primary standard in volumetric analysis, whereas KMnO4KMnO_4 is not because it can be easily reduced by impurities and is affected by light.

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The structures: CrO42βˆ’CrO_4^{2-} is tetrahedral, while Cr2O72βˆ’Cr_2O_7^{2-} consists of two tetrahedra sharing one oxygen atom with a Crβˆ’Oβˆ’CrCr-O-Cr bond angle of 126∘126^\circ.

πŸ“Formulae

4FeCr2O4+8Na2CO3+7O2β†’8Na2CrO4+2Fe2O3+8CO24FeCr_2O_4 + 8Na_2CO_3 + 7O_2 \rightarrow 8Na_2CrO_4 + 2Fe_2O_3 + 8CO_2

2Na2CrO4+2H+β†’Na2Cr2O7+2Na++H2O2Na_2CrO_4 + 2H^+ \rightarrow Na_2Cr_2O_7 + 2Na^+ + H_2O

Cr2O72βˆ’+14H++6eβˆ’β†’2Cr3++7H2O(E∘=+1.33V)Cr_2O_7^{2-} + 14H^+ + 6e^- \rightarrow 2Cr^{3+} + 7H_2O \quad (E^\circ = +1.33 V)

2MnO2+4KOH+O2β†’2K2MnO4+2H2O2MnO_2 + 4KOH + O_2 \rightarrow 2K_2MnO_4 + 2H_2O

MnO4βˆ’+8H++5eβˆ’β†’Mn2++4H2O(E∘=+1.51V)MnO_4^- + 8H^+ + 5e^- \rightarrow Mn^{2+} + 4H_2O \quad (E^\circ = +1.51 V)

2MnO4βˆ’+H2O+Iβˆ’β†’2MnO2+2OHβˆ’+IO3βˆ’Β (InΒ neutral/alkalineΒ medium)2MnO_4^- + H_2O + I^- \rightarrow 2MnO_2 + 2OH^- + IO_3^- \text{ (In neutral/alkaline medium)}

πŸ’‘Examples

Problem 1:

Write the balanced ionic equation for the reaction between acidified K2Cr2O7K_2Cr_2O_7 and Fe2+Fe^{2+} ions.

Solution:

Cr2O72βˆ’+14H++6Fe2+β†’2Cr3++6Fe3++7H2OCr_2O_7^{2-} + 14H^+ + 6Fe^{2+} \rightarrow 2Cr^{3+} + 6Fe^{3+} + 7H_2O

Explanation:

In an acidic medium, dichromate ion acts as an oxidizing agent and is reduced to Cr3+Cr^{3+}. It oxidizes ferrous ions (Fe2+Fe^{2+}) to ferric ions (Fe3+Fe^{3+}). The n-factor for Cr2O72βˆ’Cr_2O_7^{2-} is 6.

Problem 2:

What happens when KMnO4KMnO_4 reacts with H2C2O4H_2C_2O_4 (Oxalic acid) in the presence of H2SO4H_2SO_4 at 333K333K?

Solution:

2MnO4βˆ’+16H++5C2O42βˆ’β†’2Mn2++10CO2+8H2O2MnO_4^- + 16H^+ + 5C_2O_4^{2-} \rightarrow 2Mn^{2+} + 10CO_2 + 8H_2O

Explanation:

Acidified permanganate oxidizes oxalic acid to carbon dioxide gas. The reaction is slow initially but becomes fast due to the autocatalytic effect of Mn2+Mn^{2+} ions formed during the process.

Problem 3:

Explain the effect of increasing pHpH on a solution of K2Cr2O7K_2Cr_2O_7.

Solution:

Cr2O72βˆ’+2OHβˆ’β†’2CrO42βˆ’+H2OCr_2O_7^{2-} + 2OH^- \rightarrow 2CrO_4^{2-} + H_2O

Explanation:

Increasing the pHpH means adding a base. The OHβˆ’OH^- ions react with the dichromate ions (orange) to convert them into chromate ions (yellow). Thus, the color changes from orange to yellow.

Preparation and properties of K2Cr2O7 and KMnO4 Class 12 Notes & Examples