Organic Chemistry – Some Basic Principles and Techniques - Tetravalence of Carbon: Shapes of Organic Compounds
Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
Carbon has an atomic number of 6 with the electronic configuration . To form four bonds, it undergoes excitation to , demonstrating its tetravalence.
Hybridization is the process of mixing atomic orbitals to form new hybrid orbitals. In organic compounds, carbon undergoes three types of hybridization: , , and .
Hybridization: Resulting in a tetrahedral shape with bond angles of . It occurs when carbon is bonded to four other atoms via single bonds (e.g., ).
Hybridization: Resulting in a trigonal planar shape with bond angles of . It occurs when carbon is bonded to three other atoms (e.g., ), involving one bond.
Hybridization: Resulting in a linear shape with a bond angle of . It occurs when carbon is bonded to two other atoms (e.g., ), involving two bonds.
Bond Length and Strength: hybridized carbons have the shortest bond length and highest bond strength due to higher s-character, whereas has the longest bond length.
Electronegativity: The electronegativity of carbon increases with the increase in s-character. Therefore, the order is .
Sigma () bonds are formed by the axial (head-on) overlap of orbitals, while Pi () bonds are formed by the lateral (sideways) overlap of unhybridized p-orbitals.
📐Formulae
💡Examples
Problem 1:
Identify the hybridization of each carbon atom in the molecule: .
Solution:
- in is bonded to 4 atoms via bonds: .
- in is bonded to 3 atoms (one bond): .
- in is bonded to 3 atoms (one bond): .
- in is bonded to 2 atoms (two bonds): .
Explanation:
Hybridization is determined by counting the number of bonds. , , and .
Problem 2:
How many and bonds are present in the molecule ethyne ()?
Solution:
Ethyne contains bonds and bonds.
Explanation:
In ethyne, there are two single bonds () and one triple bond. A triple bond consists of and bonds. Total ; Total .