Organic Chemistry – Some Basic Principles and Techniques - IUPAC Nomenclature of Organic Compounds
Review the key concepts, formulae, and examples before starting your quiz.
🔑Concepts
The IUPAC name of an organic compound consists of three main parts: , , and . The general format is: .
The denotes the number of carbon atoms in the longest continuous chain (e.g., : Meth-, : Eth-, : Prop-, : But-).
The indicates the saturation or unsaturation in the carbon chain: for alkanes, for alkenes, and for alkynes.
The is used to represent the principal functional group (e.g., for alcohols, for aldehydes, for ketones, and for carboxylic acids).
The is used to indicate the presence of side chains or substituent groups (e.g., is methyl, is ethyl, is chloro).
Longest Chain Rule: Select the longest continuous chain of carbon atoms as the parent chain. If a functional group is present, it must be part of this chain.
Lowest Locant Rule: Number the carbon atoms of the parent chain such that the substituents or functional groups get the lowest possible locant (number).
Priority Order of Functional Groups: Substituents (Halogens, Nitro, Alkyl).
📐Formulae
💡Examples
Problem 1:
Give the IUPAC name for .
Solution:
3-chloro-2-methylbutan-1-ol
Explanation:
- The longest chain containing the group has 4 carbons (Butane). 2. Numbering starts from the carbon attached to (priority). 3. Chlorine is at and Methyl is at . 4. Alphabetically, Chloro comes before Methyl.
Problem 2:
Name the compound: .
Solution:
4-oxopentanoic acid
Explanation:
- The chain has 5 carbons. 2. The principal functional group is the carboxylic acid (), which gets the suffix '-oic acid' and position 1. 3. The ketone group () is treated as a substituent called 'oxo' at position 4.
Problem 3:
Write the IUPAC name for .
Solution:
3-methylbut-1-ene
Explanation:
- The longest chain with the double bond has 4 carbons (Butene). 2. Numbering starts from the double bond end. 3. A methyl group is present at the 3rd carbon.