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Cell: The Unit of Life - Cilia and Flagella

Grade 11CBSEBiology

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Cilia and flagella are hair-like outgrowths of the cell membrane used for locomotion and movement of surrounding fluids.

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Cilia are small structures which work like oars, causing the movement of either the cell or the surrounding fluid.

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Flagella are comparatively longer and responsible for cell movement. Prokaryotic flagella are structurally different from eukaryotic flagella.

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The electron microscopic study shows that they are covered with plasma membrane. Their core is called the axoneme, which possesses a number of microtubules running parallel to the long axis.

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The axoneme usually has nine pairs of doublets of radially arranged peripheral microtubules, and a pair of centrally located microtubules. This arrangement of axonemal microtubules is referred to as the 9+29 + 2 array.

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The central tubules are connected by bridges and are also enclosed by a central sheath, which is connected to one of the tubules of each peripheral doublet by a radial spoke. Thus, there are nine radial spokes.

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The peripheral doublets are also interconnected by linkers. Both the cilium and flagellum emerge from centriole-like structures called the basal bodies.

📐Formulae

Total microtubules in eukaryotic axoneme=(9×2)+2=20Total\ microtubules\ in\ eukaryotic\ axoneme = (9 \times 2) + 2 = 20

Peripheral doublets=9Peripheral\ doublets = 9

Central microtubules=2Central\ microtubules = 2

Number of radial spokes=9Number\ of\ radial\ spokes = 9

Axonemal arrangement=9+2Axonemal\ arrangement = 9 + 2

💡Examples

Problem 1:

In a transverse section of a eukaryotic flagellum, how many total microtubules are observed in the peripheral region and the central region combined?

Solution:

Total Microtubules = 2020

Explanation:

According to the 9+29 + 2 arrangement, there are 99 peripheral doublets (9×2=189 \times 2 = 18 microtubules) and 22 central singlets (1×2=21 \times 2 = 2 microtubules). Therefore, 18+2=2018 + 2 = 20 microtubules.

Problem 2:

Calculate the difference in the number of microtubules between a centriole (9+09 + 0 arrangement of triplets) and a cilium (9+29 + 2 arrangement of doublets).

Solution:

27−207\begin{array}{r} 27 \\ - 20 \\ \hline 7 \end{array}

Explanation:

A centriole has 99 triplets of microtubules (9×3=279 \times 3 = 27) with 00 in the center. A cilium has 99 doublets (1818) plus 22 central microtubules (18+2=2018 + 2 = 20). The difference is 27−20=727 - 20 = 7.