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States of Matter and Separation - Kinetic Theory of Matter

Grade 9IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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The Kinetic Theory of Matter states that all matter is composed of small particles (atoms, molecules, or ions) that are in constant, random motion.

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In a solid, particles are closely packed in a regular lattice, vibrating about fixed positions with low kinetic energy. The attractive forces are strong, resulting in a fixed shape and volume.

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In a liquid, particles are close together but arranged randomly. They have enough energy to slide past one another, meaning liquids have a fixed volume but take the shape of their container.

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In a gas, particles are far apart and move rapidly in all directions. They have high kinetic energy and negligible intermolecular forces, leading to no fixed shape or volume. Pressure is caused by particles colliding with the walls of a container.

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Temperature is a measure of the average kinetic energy (KEKE) of the particles. As temperature increases, particle speed increases, as shown by the relation KE=12mv2KE = \frac{1}{2}mv^2.

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Phase changes occur at constant temperature. During melting or boiling, energy is used to overcome intermolecular forces rather than increasing the speed of particles (Latent Heat).

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Diffusion is the net movement of particles from a region of higher concentration to a region of lower concentration. The rate of diffusion is inversely proportional to the square root of the molecular mass: Rate∝1MRate \propto \frac{1}{\sqrt{M}}.

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Separation techniques utilize physical properties: Filtration (solubility/size), Distillation (boiling point), and Chromatography (solubility/adsorption).

📐Formulae

T(K)=T(∘C)+273.15T(K) = T(^{\circ}C) + 273.15

KE=12mv2KE = \frac{1}{2}mv^2

Q=m×LQ = m \times L

Rf=distance moved by the substancedistance moved by the solvent frontR_f = \frac{\text{distance moved by the substance}}{\text{distance moved by the solvent front}}

💡Examples

Problem 1:

A sample of gas is at 25∘C25^{\circ}C. Convert this temperature to the Kelvin scale.

Solution:

T(K)=25+273.15=298.15 KT(K) = 25 + 273.15 = 298.15\text{ K}

Explanation:

To convert Celsius to Kelvin, the constant 273.15273.15 (often rounded to 273273 in Grade 9) is added to the Celsius value because 0 K0\text{ K} is absolute zero, equivalent to −273.15∘C-273.15^{\circ}C.

Problem 2:

In a paper chromatography experiment, a blue dye travels 4.5 cm4.5\text{ cm} from the baseline, while the solvent front travels 6.0 cm6.0\text{ cm}. Calculate the RfR_f value.

Solution:

Rf=4.5 cm6.0 cm=0.75R_f = \frac{4.5\text{ cm}}{6.0\text{ cm}} = 0.75

Explanation:

The RfR_f (retention factor) is a ratio used to identify substances. It is calculated by dividing the distance moved by the solute by the distance moved by the solvent. It has no units and is always ≤1\le 1.

Problem 3:

Compare the rate of diffusion of Ammonia (NH3NH_3, molar mass ≈17 g/mol\approx 17\text{ g/mol}) and Hydrogen Chloride (HClHCl, molar mass ≈36.5 g/mol\approx 36.5\text{ g/mol}). Which travels faster?

Solution:

RateNH3>RateHClRate_{NH_3} > Rate_{HCl}

Explanation:

According to the kinetic theory, at the same temperature, lighter particles move faster on average than heavier particles. Since NH3NH_3 (17 g/mol17\text{ g/mol}) is lighter than HClHCl (36.5 g/mol36.5\text{ g/mol}), Ammonia will diffuse faster.