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Ecology - Ecosystems and Biomes

Grade 9IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

Ecosystems consist of biotic (living) and abiotic (non-living) components interacting as a system. Abiotic factors include temperature, pHpH, sunlight intensity, and moisture levels.

The hierarchy of biological organization in ecology is: Organism \rightarrow Population \rightarrow Community \rightarrow Ecosystem \rightarrow Biome \rightarrow Biosphere.

Energy flows through an ecosystem starting from solar radiation, which is captured by producers through photosynthesis: 6CO2+6H2O+lightC6H12O6+6O26CO_2 + 6H_2O + light \rightarrow C_6H_{12}O_6 + 6O_2.

Trophic levels represent the feeding positions in a food chain. The 10%10\% rule states that only approximately 10%10\% of the energy available at one trophic level is transferred to the next, while the rest is lost as heat or used for metabolic processes.

Biomes are large-scale ecosystems defined by their climate, specifically average temperature (measured in C^\circ C) and annual precipitation (measured in mmmm). Examples include Tundra, Desert, and Tropical Rainforest.

Nutrient cycling involves the movement of elements like Carbon (CC) and Nitrogen (NN) through the biosphere. Unlike energy, nutrients are recycled within the system.

Symbiotic relationships include Mutualism (+/+)(+/+), Commensalism (+/0)(+/0), and Parasitism (+/)(+/-).

📐Formulae

6CO2+6H2OlightC6H12O6+6O26CO_2 + 6H_2O \xrightarrow{light} C_6H_{12}O_6 + 6O_2

NPP=GPPRNPP = GPP - R

Energytransfer=Energylowerlevel×0.10Energy_{transfer} = Energy_{lower\,level} \times 0.10

C6H12O6+6O26CO2+6H2O+ATPC_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O + ATP

💡Examples

Problem 1:

In a specific grassland ecosystem, the primary producers (grasses) generate 50,000kJ50,000\,kJ of energy. Calculate the energy available to the tertiary consumers (e.g., hawks) assuming the 10%10\% rule applies.

Solution:

The energy at the tertiary consumer level is 50kJ50\,kJ.

Explanation:

Starting at the producer level: 50,000kJ50,000\,kJ. Primary consumers (herbivores) receive 50,000×0.1=5,000kJ50,000 \times 0.1 = 5,000\,kJ. Secondary consumers receive 5,000×0.1=500kJ5,000 \times 0.1 = 500\,kJ. Tertiary consumers receive 500×0.1=50kJ500 \times 0.1 = 50\,kJ. This demonstrates the significant loss of energy at higher trophic levels.

Problem 2:

Identify the chemical equation for cellular respiration and explain its role in the carbon cycle.

Solution:

C6H12O6+6O26CO2+6H2O+ATPC_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O + ATP

Explanation:

Cellular respiration is the process by which organisms break down glucose (C6H12O6C_6H_{12}O_6) to release energy. In the carbon cycle, this process releases carbon dioxide (CO2CO_2) back into the atmosphere, making it available for producers to use in photosynthesis.

Ecosystems and Biomes - Revision Notes & Key Formulas | IB Grade 9 Science