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Biology - Inheritance and DNA

Grade 8IGCSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

DNA (Deoxyribonucleic Acid) is the molecule that carries genetic information. It has a double-helix structure made of two strands joined by nitrogenous bases: Adenine (AA), Thymine (TT), Cytosine (CC), and Guanine (GG).

Base pairing rules state that AA always pairs with TT (ATA-T) and CC always pairs with GG (CGC-G) via hydrogen bonds.

A gene is a short section of DNA that codes for a specific protein, which determines a particular characteristic.

Chromosomes are long, coiled molecules of DNA found in the nucleus. Humans typically have 2323 pairs of chromosomes (4646 in total). The 23rd23^{rd} pair determines sex: XXXX for female and XYXY for male.

Alleles are different versions of the same gene. An individual can be homozygous (having two identical alleles, e.g., BBBB or bbbb) or heterozygous (having two different alleles, e.g., BbBb).

The genotype refers to the genetic makeup of an organism (e.g., TtTt), while the phenotype is the physical characteristic expressed (e.g., Tall).

A dominant allele (e.g., BB) is always expressed in the phenotype if present. A recessive allele (e.g., bb) is only expressed if two copies are present (bbbb).

📐Formulae

Probability of phenotype=Number of offspring with phenotypeTotal number of offspring×100%\text{Probability of phenotype} = \frac{\text{Number of offspring with phenotype}}{\text{Total number of offspring}} \times 100\%

Phenotypic Ratio=Dominant Outcrops:Recessive Outcrops\text{Phenotypic Ratio} = \text{Dominant Outcrops} : \text{Recessive Outcrops}

Total Chromosomes=2n (where n is the haploid number)\text{Total Chromosomes} = 2n \text{ (where } n \text{ is the haploid number)}

💡Examples

Problem 1:

In pea plants, the allele for tall stems (TT) is dominant over the allele for short stems (tt). If a heterozygous tall plant (TtTt) is crossed with a short plant (tttt), what are the possible genotypes and phenotypes of the offspring?

Solution:

Genotypes: 50%50\% TtTt (heterozygous) and 50%50\% tttt (homozygous recessive). Phenotypes: 50%50\% Tall and 50%50\% Short.

Explanation:

Using a Punnett square: The gametes from the first parent are TT and tt. The gametes from the second parent are tt and tt. Crossing them gives: T×t=TtT \times t = Tt, T×t=TtT \times t = Tt, t×t=ttt \times t = tt, and t×t=ttt \times t = tt. This results in a 1:11:1 ratio.

Problem 2:

What is the probability that a child will be male (XYXY) or female (XXXX)?

Solution:

50%50\% probability for XXXX (female) and 50%50\% probability for XYXY (male).

Explanation:

The mother provides an XX chromosome. The father provides either an XX or a YY chromosome with equal probability (50%50\%). The cross XX×XYXX \times XY results in XX,XX,XY,XYXX, XX, XY, XY.