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Biology - Inheritance and DNA

Grade 8Cambridge (IGCSE)

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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DNA (Deoxyribonucleic Acid) is the molecule that carries genetic information. It has a double-helix structure made of two strands joined by nitrogenous bases: Adenine (AA), Thymine (TT), Cytosine (CC), and Guanine (GG).

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Base pairing rules state that AA always pairs with TT (A−TA-T) and CC always pairs with GG (C−GC-G) via hydrogen bonds.

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A gene is a short section of DNA that codes for a specific protein, which determines a particular characteristic.

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Chromosomes are long, coiled molecules of DNA found in the nucleus. Humans typically have 2323 pairs of chromosomes (4646 in total). The 23rd23^{rd} pair determines sex: XXXX for female and XYXY for male.

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Alleles are different versions of the same gene. An individual can be homozygous (having two identical alleles, e.g., BBBB or bbbb) or heterozygous (having two different alleles, e.g., BbBb).

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The genotype refers to the genetic makeup of an organism (e.g., TtTt), while the phenotype is the physical characteristic expressed (e.g., Tall).

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A dominant allele (e.g., BB) is always expressed in the phenotype if present. A recessive allele (e.g., bb) is only expressed if two copies are present (bbbb).

📐Formulae

Probability of phenotype=Number of offspring with phenotypeTotal number of offspring×100%\text{Probability of phenotype} = \frac{\text{Number of offspring with phenotype}}{\text{Total number of offspring}} \times 100\%

Phenotypic Ratio=Dominant Outcrops:Recessive Outcrops\text{Phenotypic Ratio} = \text{Dominant Outcrops} : \text{Recessive Outcrops}

Total Chromosomes=2n (where n is the haploid number)\text{Total Chromosomes} = 2n \text{ (where } n \text{ is the haploid number)}

💡Examples

Problem 1:

In pea plants, the allele for tall stems (TT) is dominant over the allele for short stems (tt). If a heterozygous tall plant (TtTt) is crossed with a short plant (tttt), what are the possible genotypes and phenotypes of the offspring?

Solution:

Genotypes: 50%50\% TtTt (heterozygous) and 50%50\% tttt (homozygous recessive). Phenotypes: 50%50\% Tall and 50%50\% Short.

Explanation:

Using a Punnett square: The gametes from the first parent are TT and tt. The gametes from the second parent are tt and tt. Crossing them gives: T×t=TtT \times t = Tt, T×t=TtT \times t = Tt, t×t=ttt \times t = tt, and t×t=ttt \times t = tt. This results in a 1:11:1 ratio.

Problem 2:

What is the probability that a child will be male (XYXY) or female (XXXX)?

Solution:

50%50\% probability for XXXX (female) and 50%50\% probability for XYXY (male).

Explanation:

The mother provides an XX chromosome. The father provides either an XX or a YY chromosome with equal probability (50%50\%). The cross XX×XYXX \times XY results in XX,XX,XY,XYXX, XX, XY, XY.