krit.club logo

Physics: Nuclear Physics - Atomic Nuclei, Isotopes, and Nuclear Stability

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

•

The nucleus is the small, dense, positively charged center of an atom, containing protons (p+p^{+}) and neutrons (n0n^{0}), which are collectively known as nucleons.

•

The Atomic Number (ZZ) represents the number of protons in the nucleus and defines the identity of the chemical element.

•

The Mass Number (AA) is the total number of protons and neutrons in the nucleus. The relationship is given by A=Z+NA = Z + N, where NN is the number of neutrons.

•

Isotopes are atoms of the same element that have the same number of protons (ZZ) but a different number of neutrons (NN), resulting in different mass numbers (AA).

•

Chemical properties of isotopes remain identical because they have the same electron configuration, but their physical properties (like density or boiling point) may differ due to mass differences.

•

Nuclear Stability is maintained by the Strong Nuclear Force, which acts over very short distances to overcome the electrostatic repulsion between positively charged protons.

•

For light nuclei (up to Z≈20Z \approx 20), the ratio of neutrons to protons (N:ZN:Z) is typically 1:11:1 for stability. As the atomic number increases, more neutrons are needed to provide enough strong force to keep the nucleus stable.

📐Formulae

A=Z+NA = Z + N

N=A−ZN = A - Z

Isotope Notation: ZAX\text{Isotope Notation: } {}^{A}_{Z}X

Neutron-to-Proton Ratio=NZ\text{Neutron-to-Proton Ratio} = \frac{N}{Z}

💡Examples

Problem 1:

An atom of Uranium is represented as 92238U{}^{238}_{92}U. Calculate the number of protons, neutrons, and electrons in a neutral atom of this isotope.

Solution:

Z=92Z = 92, A=238A = 238. Protons =Z=92= Z = 92. Electrons (in a neutral atom) =Z=92= Z = 92. Neutrons (NN) =A−Z=238−92=146= A - Z = 238 - 92 = 146.

Explanation:

The bottom number (ZZ) identifies the protons and electrons, while the top number (AA) is the sum of protons and neutrons. Subtracting ZZ from AA gives the neutron count.

Problem 2:

Identify the relationship between 612C{}^{12}_{6}C and 614C{}^{14}_{6}C.

Solution:

Both atoms have the same atomic number (Z=6Z = 6) but different mass numbers (1212 and 1414). Therefore, they are isotopes of Carbon.

Explanation:

Since they have the same number of protons, they belong to the same element. The difference in neutrons (66 vs 88) makes them isotopes.

Problem 3:

Calculate the mass number (AA) of an isotope of Iron (FeFe) that has 2626 protons and 3030 neutrons.

Solution:

Using the formula: A=Z+NA = Z + N A=26+30A = 26 + 30 A=56A = 56

Explanation:

The mass number is the sum of the total number of nucleons (protons and neutrons) in the nucleus.