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Chemistry: Matter, Mixtures, and Separation - Changes of State and Interconversion of Matter

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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Kinetic Molecular Theory: Matter is composed of tiny particles that are in constant motion. The kinetic energy (EkE_k) of these particles is directly proportional to the absolute temperature (TT) of the substance.

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States of Matter: Solids have a fixed shape and volume with particles vibrating in fixed positions. Liquids have a fixed volume but take the shape of their container. Gases have no fixed shape or volume and expand to fill any space, where particle distance is much greater than particle size.

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Interconversion of Matter: The process of changing from one state to another involves energy transfer. Melting (Solid to Liquid), Boiling (Liquid to Gas), and Sublimation (Solid to Gas) are endothermic processes, meaning they absorb energy (+ΔQ+\Delta Q).

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Exothermic Processes: Freezing (Liquid to Solid), Condensation (Gas to Liquid), and Deposition (Gas to Solid) release energy (−ΔQ-\Delta Q) to the surroundings.

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Heating Curves: When a substance is heated, the temperature increases until it reaches a phase change point (Melting or Boiling point). During the phase change, the temperature remains constant because the energy is used to overcome intermolecular forces of attraction rather than increasing kinetic energy.

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Evaporation vs. Boiling: Evaporation occurs only at the surface of a liquid and at any temperature, whereas boiling occurs throughout the liquid at a specific boiling point (TbT_b).

📐Formulae

Density(ρ)=mass(m)volume(V)\text{Density} (\rho) = \frac{\text{mass} (m)}{\text{volume} (V)}

T(K)=T(∘C)+273.15T(K) = T(^{\circ}C) + 273.15

Q=m×LQ = m \times L

ΔEk∝ΔT\Delta E_k \propto \Delta T

💡Examples

Problem 1:

A sample of water is at a temperature of 25∘C25^{\circ}C. Convert this temperature into the Kelvin scale.

Solution:

T(K)=25+273.15=298.15 KT(K) = 25 + 273.15 = 298.15\text{ K}

Explanation:

To convert from Celsius to Kelvin, we add 273.15273.15 to the Celsius value as 0∘C0^{\circ}C is defined as 273.15 K273.15\text{ K}.

Problem 2:

Calculate the density of a solid metal cube that has a mass of 54 g54\text{ g} and a volume of 20 cm320\text{ cm}^3.

Solution:

ρ=54 g20 cm3=2.7 g/cm3\rho = \frac{54\text{ g}}{20\text{ cm}^3} = 2.7\text{ g/cm}^3

Explanation:

Density is the ratio of mass to volume. Using the formula ρ=mV\rho = \frac{m}{V}, we divide the mass by the volume.

Problem 3:

During an experiment, a student notices that while ice is melting, the thermometer stays at 0∘C0^{\circ}C even though a Bunsen burner is heating the beaker. Why does the temperature not rise?

Solution:

The heat energy is being used as 'Latent Heat of Fusion'.

Explanation:

During a phase change from solid to liquid, the energy supplied is used to break the intermolecular bonds holding the water molecules in a rigid lattice. Since the average kinetic energy (EkE_k) of the particles does not increase during this specific process, the temperature remains constant at 0∘C0^{\circ}C until all ice has melted.