krit.club logo

Chemistry: Environmental Systems - Fertilizers, Ozone Formation, and Ozone Depletion

Grade 8IB

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

•

Fertilizers are substances added to soil to provide essential nutrients for plant growth, primarily Nitrogen (NN), Phosphorus (PP), and Potassium (KK). Nitrogen is crucial for leaf growth and protein synthesis.

•

The Haber Process is the industrial method used to produce ammonia (NH3NH_3), which is a primary component of nitrogen-based fertilizers. It involves the reversible reaction: N2(g)+3H2(g)⇌2NH3(g)N_{2(g)} + 3H_{2(g)} \rightleftharpoons 2NH_{3(g)}.

•

Eutrophication is an environmental issue where excess fertilizers wash into water bodies (leaching), causing rapid growth of algae (algal bloom). This leads to oxygen depletion and the death of aquatic life.

•

Ozone (O3O_3) in the stratosphere is formed naturally when high-energy Ultraviolet (UVUV) radiation splits oxygen molecules (O2O_2) into individual atoms, which then react with other O2O_2 molecules.

•

Ozone Depletion occurs when Chlorofluorocarbons (CFCs) reach the stratosphere and are broken down by UVUV light to release chlorine radicals (Cl⋅Cl \cdot). These radicals act as catalysts that break down ozone into oxygen gas.

•

Ground-level ozone (tropospheric ozone) is a pollutant and a major component of photochemical smog, formed by reactions between nitrogen oxides (NOxNO_x) and volatile organic compounds (VOCsVOCs) in the presence of sunlight.

📐Formulae

N2(g)+3H2(g)⇌2NH3(g)N_{2(g)} + 3H_{2(g)} \rightleftharpoons 2NH_{3(g)}

O2→UV lightO+OO_2 \xrightarrow{UV \text{ light}} O + O

O+O2→O3O + O_2 \rightarrow O_3

CFCl3→UVCFCl2+Cl⋅CFCl_3 \xrightarrow{UV} CFCl_2 + Cl \cdot

Cl⋅+O3→ClO⋅+O2Cl \cdot + O_3 \rightarrow ClO \cdot + O_2

ClO⋅+O⋅→Cl⋅+O2ClO \cdot + O \cdot \rightarrow Cl \cdot + O_2

💡Examples

Problem 1:

Calculate the percentage by mass of Nitrogen (NN) in the fertilizer Ammonium Nitrate, NH4NO3NH_4NO_3. (Relative Atomic Masses: N=14,H=1,O=16N = 14, H = 1, O = 16)

Solution:

Molar Mass of NH4NO3=(14×2)+(1×4)+(16×3)=28+4+48=80 g/mol\text{Molar Mass of } NH_4NO_3 = (14 \times 2) + (1 \times 4) + (16 \times 3) = 28 + 4 + 48 = 80 \text{ g/mol} Mass of Nitrogen=28 g/mol\text{Mass of Nitrogen} = 28 \text{ g/mol} Percentage of N=2880×100=35%\text{Percentage of } N = \frac{28}{80} \times 100 = 35\%

Explanation:

To find the nutrient content of a fertilizer, calculate the total molar mass of the compound and divide the total mass of the specific element by that molar mass, then multiply by 100.

Problem 2:

Explain why a single chlorine atom can destroy thousands of ozone molecules.

Solution:

The destruction of ozone by chlorine is a catalytic cycle. In the first step, Cl+O3→ClO+O2Cl + O_3 \rightarrow ClO + O_2. In the second step, the chlorine monoxide reacts with a free oxygen atom: ClO+O→Cl+O2ClO + O \rightarrow Cl + O_2.

Explanation:

Because the chlorine radical (Cl⋅Cl \cdot) is regenerated at the end of the second reaction, it is free to attack another ozone molecule. This chain reaction allows a single radical to deplete a significant amount of ozone until it eventually reacts with another species to form a stable compound.