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The Amazing World of Solutes, Solvents, and Solutions - Factors Affecting Dissolution Rate

Grade 8CBSE

Review the key concepts, formulae, and examples before starting your quiz.

🔑Concepts

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A Solution is a homogeneous mixture of two or more substances. The substance present in smaller quantity is the Solute, and the substance in larger quantity is the Solvent.

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Dissolution is the process where a solute integrates into a solvent to form a solution. Common examples include dissolving salt (NaClNaCl) or sugar (C12H22O11C_{12}H_{22}O_{11}) in water (H2OH_2O).

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Temperature: Increasing the temperature increases the kinetic energy of the solvent molecules. This leads to more frequent collisions between the solvent and solute, increasing the rate of dissolution.

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Surface Area (Particle Size): Smaller particles have a larger surface area per unit mass. For example, powdered sugar dissolves faster than a sugar cube because more solute molecules are exposed to the solvent (H2OH_2O) simultaneously.

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Stirring (Agitation): Stirring moves the dissolved solute away from the surface of the solid, bringing fresh solvent into contact with the solute, thereby speeding up the process.

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Saturated Solution: A solution in which no more solute can be dissolved at a specific temperature. The point of saturation depends on the nature of the solute and the temperature (TT).

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Solubility: The maximum amount of solute that can be dissolved in 100 g100 \text{ g} of a solvent at a specified temperature.

📐Formulae

Mass of Solution=Mass of Solute+Mass of Solvent\text{Mass of Solution} = \text{Mass of Solute} + \text{Mass of Solvent}

Concentration (Mass/Mass %)=(Mass of SoluteMass of Solution)×100\text{Concentration (Mass/Mass \%)} = \left( \frac{\text{Mass of Solute}}{\text{Mass of Solution}} \right) \times 100

Concentration (Mass/Volume %)=(Mass of SoluteVolume of Solution)×100\text{Concentration (Mass/Volume \%)} = \left( \frac{\text{Mass of Solute}}{\text{Volume of Solution}} \right) \times 100

💡Examples

Problem 1:

A solution is prepared by dissolving 40 g40 \text{ g} of common salt (NaClNaCl) in 320 g320 \text{ g} of water (H2OH_2O). Calculate the concentration in terms of mass by mass percentage of the solution.

Solution:

Mass of solute=40 g\text{Mass of solute} = 40 \text{ g} Mass of solvent=320 g\text{Mass of solvent} = 320 \text{ g} Mass of solution=40 g+320 g=360 g\text{Mass of solution} = 40 \text{ g} + 320 \text{ g} = 360 \text{ g} Concentration=40360×100=11.1%\text{Concentration} = \frac{40}{360} \times 100 = 11.1\%

Explanation:

To find the concentration, we first find the total mass of the solution by adding the solute and solvent. Then, we apply the mass percentage formula.

Problem 2:

Why does a crystal of potassium permanganate (KMnO4KMnO_4) dissolve faster in hot water than in cold water?

Solution:

In hot water, the particles have higher Kinetic Energy (KE=12mv2KE = \frac{1}{2}mv^2).

Explanation:

At higher temperatures, solvent molecules move faster and collide with the KMnO4KMnO_4 crystals with more force and frequency, breaking the inter-particle forces of the solute more quickly.